The account already has $278
If you add and then subract 278 then the value will be the same
Your answer is B
Hopw this helps
-GoldenWolfX✔
It's hard to visually inspect a description of the plot. Let's calculate.
A = ( 1(65) + 1(67) + 1(77) + 1(79) + 1(88) + 1(90) + 2(92)+1(100)+2(102)+1(109)+1(110)+2(112)+1(122)+1(136)+1(139)) / 18 = 99.7
B = ( 2(50)+1(55)+1(61)+2(70)+2(80)+2(89)+1(95)+3(100)+1(110)+1(114))/ 16=82.1
Group A averaged around 17 or 18 seconds longer.
Answer: Group A
$ 2000 is invested at 3 % interest and $ 4000 is invested at 8 % interest
<em><u>Solution:</u></em>
Given that, total of $6000 was invested
Let "x" be the amount invested at 3 % interest
Then, (6000 - x) is the amount invested at 8 % interest
Given that,
<em><u>The total yearly interest amounted to $380</u></em>
Then, we can frame a equation as:

<em><u>Solve the above expression for "x"</u></em>

Thus, $ 2000 is invested at 3 % interest
(6000 - x) = 6000 - 2000 = 4000
$ 4000 is invested at 8 % interest
Answer:
A) 1790.85
Step-by-step explanation:
Hi there!
In order to solve this problem, you’ll need to use the compound interest formula 
p will be your principle, or starting amount, which is 1,000.
r will be your percentage, which is 0.06.
n will be the amount of times interest is compounded, since this question says compounded anually, your compound will be 1.
t is the time in years it is compounded, which is 10.
When the numbers are plugged in, we get 
When we solve for this, we get 1790.85.
Hope this helps! :)