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Anika [276]
3 years ago
8

Lines AB and CD intersect at E.Lines A B and C D intersect at point E. Angle A E C is 50 degrees.Type the answers to each questi

on in the boxes below.a. What is the measure of angle AED?degreesExplain how you know.Type your response in the space below.b. What is the measure of angle DEB?degreesExplain how you know.Type your response in the space below.
Mathematics
1 answer:
aniked [119]3 years ago
5 0

The measure of angle AED and angle DEB are 130 and 50degrees respectively.

The point that bisects a line divides the line into two equal parts.

If the line AB and CD intersects at E, then;

  • AEC and AED supplementary
  • <AEC + <AED = 180 degrees

Given that <AEC = 50 degrees

<AED = 180 - <AEC

<AED = 180 - 50

<AED = 130degrees

Similarly, <AED and <DEB are supplementary

<AED + <DEB = 180

<DEB = 180  - <AED

<DEB = 180 - 130

<DEB = 50 = <AEC (vertically opposite)

The measure of angle AED and angle DEB are 130 and 50degrees respectively.

Learn more here; brainly.com/question/14941189

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The account already has $278

If you add and then subract 278 then the value will be the same

Your answer is B

Hopw this helps

-GoldenWolfX✔

7 0
3 years ago
Read 2 more answers
The dot plot below shows the amount of time two random groups of students took to solve a puzzle:
Natalka [10]

It's hard to visually inspect a description of the plot. Let's calculate.


A = ( 1(65) + 1(67) + 1(77) + 1(79) + 1(88) + 1(90) + 2(92)+1(100)+2(102)+1(109)+1(110)+2(112)+1(122)+1(136)+1(139)) / 18 = 99.7


B = ( 2(50)+1(55)+1(61)+2(70)+2(80)+2(89)+1(95)+3(100)+1(110)+1(114))/ 16=82.1



Group A averaged around 17 or 18 seconds longer.


Answer: Group A



6 0
4 years ago
A total of $6000 was invested, part of it at 3% interest and the remainder at 8%. If the total yearly interest amounted to $380,
Nastasia [14]

$ 2000 is invested at 3 % interest and $ 4000 is invested at 8 % interest

<em><u>Solution:</u></em>

Given that, total of $6000 was invested

Let "x" be the amount invested at 3 % interest

Then, (6000 - x) is the amount invested at 8 % interest

Given that,

<em><u>The total yearly interest amounted to $380</u></em>

Then, we can frame a equation as:

x \times 3 \% + (6000 - x) \times 8 \% = 380

<em><u>Solve the above expression for "x"</u></em>

x \times \frac{3}{100} + (6000-x) \times \frac{8}{100} = 380\\\\0.03x + (6000-x) \times 0.08 = 380\\\\0.03x + 480 - 0.08x = 380\\\\-0.05x = -100\\\\\text{Divide both sides by -0.05 }\\\\x = 2000

Thus, $ 2000 is invested at 3 % interest

(6000 - x) = 6000 - 2000 = 4000

$ 4000 is invested at 8 % interest

4 0
4 years ago
You invest $1,000 in an account with 6 % interest, compounded annually. Assume you do not touch the money or add money other tha
IRISSAK [1]

Answer:

A) 1790.85

Step-by-step explanation:

Hi there!

In order to solve this problem, you’ll need to use the compound interest formula x = p(1 + \frac{r}{n} )^n^t

p will be your principle, or starting amount, which is 1,000.

r will be your percentage, which is 0.06.

n will be the amount of times interest is compounded, since this question says compounded anually, your compound will be 1.

t is the time in years it is compounded, which is 10.

When the numbers are plugged in, we get x = 1,000(1 + \frac{0.06}{1})^1^0

When we solve for this, we get 1790.85.

Hope this helps! :)

5 0
3 years ago
Solve the equation for b. b/2q=h+7
grin007 [14]

\dfrac{b}{2q}=h+7\qquad\text{multiply both sides by 2q}\neq0\\\\b=2q(h+7)\qquad\text{use distributive property}\\\\b=(2q)(h)+(2q)(7)\\\\\boxed{b=2hq+14q}

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