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zhenek [66]
3 years ago
6

A solid metal cube of side 3 inches is placed in a rectangular tank whos length, width, and height are 3, 4 and 5 inches, respec

tively. what is the volume, in cubic inches, of water that the tank can now hold.
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
5 0
To solve this problem you must apply the proccedure shown below:

 1. Yoy have that the <span>rectangular tank has the following dimensions:

 Length=3 inches
 Widht=4 inches
 Height=5 inches

 2. Then, its volume is:

 V1=LxWxH
 V1=3 inchesx4 inchesx5 inches
 V=60 inches</span>³

 3. The sides of the <span>solid metal cube are of 3 inches, therefore, its volume is:

 V2=s</span>³
 V2=(3 inches)³
 V2=27 inches³

 4. T<span>he volume, in cubic inches, of water that the tank can now hold is:

 Vt=V1-V2
 Vt=60 inches</span>³-27 inches³
 Vt=33 inches³
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Answer:

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This is easier to see if you use the expanded notation.

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