Evaluate the expression. 62. (16 +19) - 103
2 answers:
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Answer:
(Explanation)
Step-by-step explanation:
Part A:
The graph of y = + 2 will be translated 2 units up from the graph of y =
.
If you plug in 0 for x, you get a y-value of 2. The 2 is also not included with the , which is why it doesn't translate left.
This is what graph A should look like:
[Attached File]
Part B:
The graph of y = - 2 will be translated 2 units down from the graph of y =
.
If you plug in 0 for x, you get a y-value of -2. The 2 is also not included with the , which is why it doesn't translate right.
This is what graph B should look like:
[Attached File]
Part C:
The graph of y = 2 is a stretched version of the graph y =
. Numbers that are greater than 1 stretch and open up and numbers less than -1 stretch and open down.
This is what graph C should look like:
[Attached File]
Part D:
The graph of y = is a compressed version of the graph y =
. Numbers that are in-between 0 and 1, and -1 and 0 are compressed.
This is what graph D should look like:
[Attached File]
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Answer:
- 0 ≤ m ≤ 7
- 0.4541 cm/month; average rate of growth over last 4 months of study
Step-by-step explanation:
<u>Part A</u>:
The study was concluded after 7 months. The fish cannot be expected to maintain exponential growth for any significant period beyond the observation period. A reasonable domain is ...
0 ≤ m ≤ 7
__
<u>Part B</u>:
The y-intercept is the value when m=0. It is the length of the fish at the start of the study.
__
<u>Part C</u>:
The average rate of change on the interval [3, 7] is given by ...
(f(7) -f(3))/(7 -3) = (4(1.08^7) -4(1.08^3))/4 = 1.08^3·(1.08^4 -1)
≈ 0.4541 cm/month
This is the average growth rate of the fish in cm per month over the period from 3 months to 7 months.
