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2 years ago

What is the midline equation for the function h(x)=−3cos(πx+2)−6?

Mathematics

1 answer:

Rus_ich [418]2 years ago

6 0

Answer:

y = -6

Step-by-step explanation:

y=acos(bx+c)+d

d = -6 .. vertical shift

midline: y = -6

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Quadrilateral ABCD has the following

a_sh-v [17]

Answer:

No because the angle of point C is NOT congruent to the angle of point A.

Step-by-step explanation:

A quadrilateral MUST be a parallelogram if it has both pairs of its opposite angles congruent.

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2 years ago

Let P = 0.5 0.1 0.5 0.9 be the transition matrix for a Markov chain with two states. Let x0 = 0.5 0.5 be the initial state vecto

max2010maxim [7]

Answer:

Complete solution is given in the images attached below for better demonstration

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2 years ago

Write a definite integral that represents the area of the region. (Do not evaluate the integral.)

joja [24]

Answer:

$\int_{-1}^{1}7(x^{3}-x)\:dx$

Step-by-step explanation:

1) The other curve is $y=0$ then the common points of both curves are x-intercepts, the roots of $y=7(x^{3}-x)$

$y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )$

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

$\int_{a}^{b}|f(x)-g(x)dx$

$\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx$

8 0

3 years ago

Simplify the expression 5+4+2(-3)+7+(-5)

liberstina [14]

Just use pemdas
(Parenthesis, exponents, multiplication, division, addition, subtraction)

4 0

3 years ago

Each side of the base of a right square pyramid is multiplied by 12, but the height is not changed. By what factor is the volume

drek231 [11]

Answer:

the formula for a square pyramid is $a^{2}$ $\frac{h}{3}$ so I THINK its B please do not base ur answer from my opinion

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers