Answer:
Step-by-step explanation:
<u>Eigenvalues of a Matrix</u>
Given a matrix A, the eigenvalues of A, called 
are scalars who comply with the relation:
Where I is the identity matrix
![I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=I%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
The matrix is given as
![A=\left[\begin{array}{cc}3&5\\8&0\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%265%5C%5C8%260%5Cend%7Barray%7D%5Cright%5D)
Set up the equation to solve
![det\left(\left[\begin{array}{cc}3&5\\8&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda \end{array}\right]\right)=0](https://tex.z-dn.net/?f=det%5Cleft%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%265%5C%5C8%260%5Cend%7Barray%7D%5Cright%5D-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Clambda%260%5C%5C0%26%5Clambda%20%5Cend%7Barray%7D%5Cright%5D%5Cright%29%3D0)
Expanding the determinant
![det\left(\left[\begin{array}{cc}3-\lambda&5\\8&-\lambda\end{array}\right]\right)=0](https://tex.z-dn.net/?f=det%5Cleft%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3-%5Clambda%265%5C%5C8%26-%5Clambda%5Cend%7Barray%7D%5Cright%5D%5Cright%29%3D0)
Operating Rearranging
Factoring
Solving, we have the eigenvalues
Answer:
what you said means this in algebraic terms
6>-(6×x)
Step-by-step explanation:
to solve it 6(>-6×6)
1 Divide both sides by -6
-1<x
2 Switch sides.
x>-1
9514 1404 393
Answer:
50 ft
Step-by-step explanation:
The side lengths in a 30-60-90 triangle have the ratios 1 : √3 : 2. The longest side is 2 times the length of the shortest side.
In this geometry, that means the length of the escalator is 2 times its height, so is ...
x = 2(25 ft)
x = 50 ft . . . . . distance a person travels
The equation would be 4x+5y=6.33 and 3x+3y=4.11
so from their you would do the calculations and get 0.52 and 0.85
To make sure the caluclations aare right you just hae to put in the numbers for the x and y
4(0.52)+5(0.85)=6.33
So 1 donutis $).52
1 large coffee is $0.85
Given,
The linear pair of the equation is,
Required
The solution of the linear equation.
Taking the equation first as,
Substituting the value of y in second equation then,
Substituting the value of x in first equation then,
Hence, the solution of the system is (1, -10).
