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trapecia [35]
3 years ago
12

Strings with 4 factors to get to 840

Mathematics
1 answer:
alisha [4.7K]3 years ago
8 0
2 x 420

3 x 280

4 x 210

5 x 168

6 x 140

7 x 120

8 x 105

10 x 84

12 x 70

14 x 60

15 x 56

20 x 24

21 x 40

24 x 35

28 x 30

2 x 2 x 210

2 x 3 x 140

2 x 5 x 84

2 x 7 x 60

3 x 5 x 56

3 x 7 x 40

5 x 7 x 24

2 x 2 x 2 x 105

2 x 2 x 3 x 70

2 x 2 x 5 x 42

2 x 2 x 7 x 30

2 x 3 x 5 x 28

2 x 3 x 7 x 20

3 x 5 x 7 x 8

2 x 2 x 2 x 3 x 35

2 x 2 x 2 x 5 x 21

2 x 2 x 2 x 7 x 15

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Can someone explain how to do this?
Tems11 [23]
         x+7
------------------- =       
  x^2+4x -21

         x+7
= -------------------
    (x+7)(x-3)

       1
= ----------  where x is not equal -7 and 3
    x - 3

answer is A. first choice
4 0
3 years ago
PLEASE HELP!! URGENT!! i will mark brainliest if its right!! In the figure below, ∠DEC ≅ ∠DCE, ∠B ≅ ∠F, and DF ≅ BD. Point C is
zvonat [6]

Answer:

See below.

Step-by-step explanation:

This is how you prove it.

<B and <F are given as congruent.

This is 1 pair of congruent angles for triangles ABC and GFE.

<DEC and <DCE are given as congruent.

Using vertical angles and substitution of transitivity of congruence of angles, show that angles ACB and GEF are congruent.

This is 1 pair of congruent angles for triangles ABC and GFE.

Now you need another side to do either AAS or ASA.

Look at triangle DCE. Using the fact that angles DEC and DCE are congruent, opposite sides are congruent, so segments DC and DE are congruent. You are told segments DF and BD are congruent. Using segment addition postulate and substitution, show that segments CB and EF are congruent.

Now you have 1 pair of included sides congruent ABC and GFE.

Now using ASA, you prove triangles ABC and GFE congruent.

7 0
3 years ago
0<br> 1<br> 2<br> 3<br> 4<br> 5.<br> 6<br> I don’t know what I’m doing
IgorC [24]

Answer:

cool

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Solve the following proportion for v. V/13=11/13
NeX [460]

Answer:

V = 11

Step-by-step explanation:

All you have to do here is to multiply both sides of this equation by 13.  This will eliminate the fractions.  You'll be left with V = 11.

8 0
3 years ago
The perimeter of a △ABC equals 12 in. The midpoints of the sides M, N and K are connected consecutively. Find the perimeter of △
Assoli18 [71]

The answer is 6. Sorry, I don't know why though.

8 0
3 years ago
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