All categories

3 years ago

HELP ANSWER QUICKLY PLS!!!!!

Mathematics

1 answer:

ollegr [7]3 years ago

6 0

Answer:

Either B or C, most likely B tho

Step-by-step explanation:

You might be interested in

Billy is going to share 2 1/2 pizzas with

svet-max [94.6K]

Answer:

5/6

Step-by-step explanation:

2 1/2 -> 5/2

5/2 divided by 3, which is 0.83333333333

0.83333333333 as a simplied fraction is 5/6

4 0

2 years ago

about 47% of the 15152 samples researchers found were bacteria. what percent of the samples were not bacteria?

timofeeve [1]

47% of them were bacteria, which means 53% of them were not bacteria.

47+53=100 or 100-47=53

I hope this helps :)

3 0

3 years ago

79+65<br> leave change change

vampirchik [111]

144 I believe
---
veronica howard

6 0

3 years ago

If you needed only 1 c of milk, what is your best choice at the grocery store? a quart container, a pint container, or a 1/2 gal

Lena [83]

What would be best to buy is the quart container

8 0

3 years ago

A recent survey based on a random sample of n=470 voters, predicted that independent candidate for the mayoral election will get

julsineya [31]

I have an expression

$\sigma = \sqrt{p(1-p)/n}$

floating around in my head; let's see if it makes sense.

The variance of binary valued random variable b that comes up 1 with probability p (so has mean p) is

$E( (b-p)^2 ) = (-p)^2(1-p) + (1-p)^2p = p(1-p)$

That's for an individual sample. For the observed average we divide by n, and for the standard deviation we take the square root:

$\sigma = \sqrt{p(1-p)/n}$

Plugging in the numbers,

$\sigma = \sqrt{.24(1-.24)/490} = 0.019 = 1.9\%$

One standard deviation of the average is almost 2% so a 27% outcome was 3/1.9 = 1.6 standard deviations from the mean, corresponding to a two sided probability of a bit bigger than 10% of happening by chance.

So this is borderline suspect; most surveys will include a two sigma margin of error, say plus or minus 4 percent here, and the results were within those bounds.

7 0

3 years ago