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irina1246 [14]
2 years ago
14

What restrictions did the Coercive Acts place on the Massachusetts colonists after the Boston Tea Party?

Advanced Placement (AP)
1 answer:
viktelen [127]2 years ago
6 0

Answer:

D. They closed the Boston Harbor and limited (but did not withdraw) the colony's right to govern itself

Explanation:

On May 10, 1773, the British Parliament passed the <u>Tea Act</u>. This act allowed British companies to ship tea to the colonies without duties, but the colonists still had to pay a tax on tea.

They were outraged at this display of "taxation without representation", so they tried to boycott the tea and force the ships to return to Britain. This didn't work, so they moved onto their next plan: <u>The Boston Tea Party.</u> On December 10, 1773, a group known as the Sons of Liberty disguised themselves and boarded the ship. They threw thousands of pounds of British tea into the Boston Harbor.

The British found out and they were angry and shocked. They realized the colonies were out of control, so they passed the <u>Coercive/Intolerable Acts.</u> These:

  • Closed the Boston Harbor
  • Placed the colony under direct British control
  • Prevented trials of British officials from occurring in the colonies
  • Required British soldiers to be quartered at the colonists' expense

The correct answer is D. They closed the Boston Harbor and limited (but did not withdraw) the colony's right to govern itself. The colony had some power, but it was extremely limited.

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<h3>What is probability? </h3>

Probability can be defined as the likelihood of an event to occur. In statistics, the mean of the sample distribution typically shows the probability of the population.

From the parameters given:

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The sample proportion \mathbf{\hat p} can be computed by using the expression:

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If the percentage of the probability of all patients in the emergency room = 0.75

The probability that the proportion of patients who wait less than 30 minutes is 0.582 or less can be computed as:

\mathbf{( \hat P \leq 0.582) = P \Big( \dfrac{\hat p - p}{\sqrt{\dfrac{p(1-p)}{n}}} \leq \dfrac{0.582 - 0.75}{\sqrt{\dfrac{0.75(1-0.75)}{55}}} \Big )}

\mathbf{( \hat P \leq 0.582 )= P \Big( Z \leq \dfrac{-0.168}{\sqrt{0.003409}} \Big )}

\mathbf{( \hat P \leq 0.582) = P \Big( Z \leq -2.88 \Big )}

From the Z distribution table:

\mathbf{( \hat P \leq 0.582) = 0.00198}

\mathbf{( \hat P \leq 0.582) \simeq 0.0020}

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brainly.com/question/24756209

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