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3 years ago

What is the LCM of 21 and 35

Mathematics

1 answer:

bezimeni [28]3 years ago

5 0

Answer:105

Step-by-step explanation:

becasue you can mutiply 35 3 times and 21 5 times and you get the same number as 105

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Please help me as soon as possible. Thank you

gavmur [86]

2x + y = 3 is the blue boundary line...the shading is below the line which means 2x + y is less than or equal to 3

y - x = 2 is the red boundary line... the shading is above the line which means
y - x is greater than or equal to 2

ANSWER: 2x + y is less than or equal to 3 and y - x is greater than or equal to 2

5 0

3 years ago

Solve equation below 25= y over 4 + 22

dolphi86 [110]

Answer:

y=650

Step-by-step explanation:

First add 25=y/(4+22) to get 25=y/26 then multiply both sides by 26 for y=650

7 0

4 years ago

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IM STRESSED OUT AND MY TEACHER ALREADY CALLED MY MOM

kondaur [170]

Answer:

B. 1 8/21

Step-by-step explanation:

trust

5 0

3 years ago

Read 2 more answers

If the gradient of the tangent to

Marizza181 [45]

Answer:

Point A(9, 3)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Anything to the 0th power is 1
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = \sqrt{x}$

$\displaystyle y' = \frac{1}{6}$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y = x^{\frac{1}{2}}$
Basic Power Rule: $\displaystyle y' = \frac{1}{2}x^{\frac{1}{2} - 1}$
Simplify: $\displaystyle y' = \frac{1}{2}x^{-\frac{1}{2}}$
[Derivative] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{1}{2x^{\frac{1}{2}}}$
[Derivative] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y' = \frac{1}{2\sqrt{x}}$

Step 3: Solve

Find coordinates of A.

x-coordinate

Substitute in y' [Derivative]: $\displaystyle \frac{1}{6} = \frac{1}{2\sqrt{x}}$
[Multiplication Property of Equality] Multiply 2 on both sides: $\displaystyle \frac{1}{3} = \frac{1}{\sqrt{x}}$
[Multiplication Property of Equality] Cross-multiply: $\displaystyle \sqrt{x} = 3$
[Equality Property] Square both sides: $\displaystyle x = 9$