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3 years ago

HELPP PLS ASAP I NEED HELP

Mathematics

1 answer:

AysviL [449]3 years ago

4 0

Answer:

Option (b) second one is the correct answer

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The area of a isosceles trapezoid height of 8 base of 10 base of 15

ikadub [295]

Answer:

A = 100 $un^{2}$

Step-by-step explanation:

You have to use the area of a trapezoid formula:

A = $\frac{h}{2}$ (a + b)

Now, substitute the values of the height and the bases:

A = $\frac{8}{2}$ (10 + 15)

Finally, simplify the equation to solve for the area:

A = 4(25)

A = 100 $un^{2}$

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3 years ago

Given f(x)= (4x+1)/3 solve for f^-1(3)

nirvana33 [79]

I hope this helps you

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3 years ago

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Jamal makes $12.00/hour and worked 9 hours today. What is his total pay? Don't forget to calculate overtime pay.

Elanso [62]

Answer:

He made $108 in 9 hours

Step-by-step explanation:

I first multiplied 12 by 9 and got 108

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4 years ago

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Find the derivative of the following. please show the steps when you answer :1) f(x) = 8xe^x2) y= 5xe^x^43) f(x)= x^8+5/x4) f(t)

borishaifa [10]

Answer:

Since,

$\frac{d}{dx}x^n = nx^{n-1}$

$\frac{d}{dx}(f(x).g(x)) = f(x).\frac{d}{dx}(g(x)) + g(x).\frac{d}{dx}(f(x))$

$\frac{d}{dx}(\frac{f(x)}{g(x)})=\frac{g(x).f'(x) - f(x) g'(x)}{(g(x))^2}$

1) $y = 8x e^x$

Differentiating with respect to x,

$\frac{dy}{dx}=8( x \times e^x + e^x) = 8(xe^x + e^x) = 8e^x(x+1)$

2) $y = 5x e^{x^4}$

Differentiating w. r. t x,

$\frac{dy}{dx}=5(x\times 4x^3 e^{x^4}+e^{x^4})=5e^{x^4}(4x^4+1)$

3) $y = x^8 + \frac{5}{x^4}$

Differentiating w. r. t. x,

$\frac{dy}{dx}=8x^7 - \frac{5}{x^5}\times 4 = 8x^7 - \frac{20}{x^5}=\frac{8x^{12}-20}{x^5}$

4) $f(t) = te^{11}-6t^5$

Differentiating w. r. t. t,

$f'(t) = e^{11} - 30t^4$

5) $g(p) = p\ln(2p+3)$

Differentiating w. r. t. p,

$g'(p) = p\frac{1}{2p+3}(2) + \ln(2p+3) = \frac{2p}{2p+3}+\ln(2p+3)$

6) $z = (te^{6t}+e^{5t})^7$

Differentiating w. r. t. t,

$\frac{dz}{dt}=7(te^{6t}+e^{5t})^6 ( 6te^{6t}+e^{6t} + 5e^{5t})$

7) $w =\frac{2y + y^2}{7+y}$

Differentiating w. r. t. y,

$\frac{dw}{dy} = \frac{(7+y)(2+2y)-(2y+y^2)}{(7+y)^2} = \frac{14 + 2y + 14y +2y^2 - 2y - y^2}{(7+y)^2}=\frac{14+14y+y^2}{(7+y)^2}$

7 0

3 years ago

Could ΔABC be congruent to ΔADC by SSS? Explain. Yes, but only if AB ≅ DC. Yes, but only if BC ≅ DC. No, because AB is not congr

Sonbull [250]

Answer:

<em>Yes, but only if BC ≅ DC; Option B</em>

Step-by-step explanation:

There are 4 possible ways to determine whether two triangles are congruent, and they are the following ;

ASA ( Angle - Side - Angle ),

SAS ( Side - Angle - Side ),

AAS ( Angle - Angle - Side ), and

SSS ( Side - Side - Side )

It is known here that we must prove these triangles congruence through SSS. A triangle can thus be made possible through the congruence of corresponding sides;

Now if we were to create these triangles it would be that BC and DC are, if the triangles were to coincide with one another, the apparent same length if it were that these two Δs really are ≅. Thus;

<em>Solution; Yes, but only if BC ≅ DC</em>

5 0

3 years ago