Answer:
x^2 + (x + 2)^2 = 202
x^2 + x^2 + 4x + 4 = 202
2x^2 + 4x + 4 = 202
2x^2 + 4x - 198 = 0
x^2 + 2x - 99 = 0
x = -2/2 ± √((2/2)^2 - (-99))
x = 9 or x = -11
-11 is not a positive number so the number is 9.
<span>70 grams of fat is pretty high, so we can just guess and check
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Anything withdrawn you subtract. Then, you know the total and you know what you had. Subtract total from what you had and you will see the change.
1735.97-100=1635.97
1668.71-1635.97=32.74
The zeroes of <span>f(x) = x^5-12x^2+32x can be found by factoring,
</span><span>f(x) = x^5-12x^2+32x=(x-8)(x-4)
By the zero product theorem, (x-8)=0 or (x-4)=0 which means
x=8 or x=4.
So the zeroes of f(x) are S={4,8}</span>
Good evening
Answer:
<h2>384</h2>
Step-by-step explanation:
s = 8 ⇒ 6s^2 = 6(8)²
= 6×64
= 384
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:)