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3 years ago

40. Resuelve la siguiente operación.

Mathematics

2 answers:

Naddik [55]3 years ago

7 0

Option B is correct. The required expression on expansion of 20х-[2х -(х+2)-(6-x 2 )-(28 +x+x2] is 20x + 36

Expressions are function that does not include "equal" sign

Given the expression

20х-[2х -(х+2)-(6-x² )-(28 +x+x2]

Expand and collect the like terms

= 20х-[2х -х-2-6+x² -28 - x - x²]

= 20x - [x - 8 + x² - 28 - x - x² ]

x and x² cancels out from the expression to have

= 20x - [- 8 - 28]

= 20x -(-36)

= 20x + 36

Hence the required expression on expansion is 20x + 36

Learn more here: brainly.com/question/12293021

zimovet [89]3 years ago

3 0

Answer: B 20x +36

Step-by-step explanation: esa respuesta es la correcta

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Answer:

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Step-by-step explanation:

5x+2y=8

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4 years ago

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finlep [7]

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3 years ago

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3 years ago

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beks73 [17]

<h2>Answer:</h2>

The derivative of the function f(x) is:

$f'(x)=-2x$

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as:

$f(x)=5-x^2$

We have:

$f(x+h)=5-(x+h)^2\\\\i.e.\\\\f(x+h)=5-(x^2+h^2+2xh)$

( Since,

$(a+b)^2=a^2+b^2+2ab$ )

Hence, we get:

$f(x+h)=5-x^2-h^2-2xh$

Also, by using the definition of f'(x) i.e.

$f'(x)= \lim_{h \to 0} \dfrac{f(x+h)-f(x)}{h}$

Hence, on putting the value in the formula:

$f'(x)= \lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-(5-x^2)}{h}\\\\\\f'(x)=\lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-5+x^2}{h}\\\\i.e.\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2-2xh}{h}\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2}{h}+\dfrac{-2xh}{h}\\\\f'(x)=\lim_{h \to 0} -h-2x\\\\i.e.\ on\ putting\ the\ limit\ we\ obtain:\\\\f'(x)=-2x$

Hence, the derivative of the function f(x) is:

$f'(x)=-2x$

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3 years ago

Read 2 more answers

A 16-ounce bottle of orange juice says that it contains 200 milligrams of vitamin C, which is 250% of the daily recommended dosa

Andrei [34K]

80 milligrams is the amount of vitamin C that is considered to be 100% of the daily recommended requirement for adults.

<h3>What is the daily recommended dosage of vitamin C for adults? </h3>

Parameter

The amount of liquid included in the bottle is 16 ounces.
The vitamin C content of the bottle comes to a total of 200 milligrams.

Since the orange juice container that has a capacity of 16 ounces states that it has 200 milligrams of vitamin C, this means that it fulfills 250% of an adult's recommended daily requirement for vitamin C. Then, for one hundred percent of the daily allotment,

As a result, we are able to draw the conclusion that the amount of vitamin C that is considered to be 100% of the daily recommended requirement for people is 80 milligrams.