Combining the operations
The allowed operations are:
Add the same amount to both sides (either x's or ones)
Subtract the same amount from both sides (either x's or ones)
Multiply both sides by the same number (but not by zero)
Divide both sides by the same number (but not by zero)
(There are others, too, but they are not needed in simple equations.)
The goal is to FIRST add and subtract until we have ONLY x's (blocks) on one side and ONLY ones (circles) on the other. Then, if you have more than one block, you need to divide so as to arrive to the situation with only one block on the one side, which is the solved equation!
If s is the side of the square base, the area of the square base is s^2.
The volume of the square base is,
V = (s²) (h)
s² = V/h
s² = 3n³ + 13n² + 16n + 4 / <span>3n + 1
You can do this division by factoring, synthetic division, or by plain division.
Factoring out 3n + 1 from the numerator gives you:
</span>s² = (3n + 1)(n² + 4n + 4) / 3n+1
s² = n² + 4n + 4
Therefore, the area of the square base is <span>n² + 4n + 4.</span>
Answer:
2 × 2 × 3 × 5
Step-by-step explanation:
Given that,
The number = 60
To find,
Factors of 60 greater than 1 = ?
Procedure:
As we know,
Any of various numbers multiplied together to form a whole.
To find the factors of a number, we will have to do its prime factorization.
So,
The prime factorization of 60:
1 * 2 * 2 * 3 * 5 = 60
Since the factors greater than 1 are asked, the factors would be;
2 * 2 * 3 * 5
Thus, 2 * 2 * 3 * 5 is the correct answer.
