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3 years ago

Find the value of k such that the line through (k + 3, 7) and (-5,3 – k) has a slope of 3/5

Mathematics

1 answer:

Nookie1986 [14]3 years ago

8 0

Answer:

k = 2

Step-by-step explanation:

slope = rise/run = (y1 - y2) / (x1 - x2)

s = (7 - (3-k)) / ((k+3) - (-5)) give slope is 3/5

3/5 = (7 - (3-k)) / ((k+3) - (-5)) then multiply both sides by ((k+3) - (-5))

(3/5)((k+3) - (-5)) = (7 - (3-k))

(3/5)(k+3+5) = 7 - 3 + k

(3/5)(k+8) = 4 + K

3k/5 + 24/5 = 4 + k

3k/5 - k = 4 - 24/5

3k/5 - 5k/5 = 20/5 - 24/5

-2k/5 = -4/5

-2k = -4

k = 2

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3 years ago

Accumulated Amount of Money Flow An investment is expected to yield a uniform continuous rate of money flow of $20,000 per year

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Amount after 3 years will be $22496

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Amount is given by $A=P(1+\frac{r}{100})^n$

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