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erik [133]
2 years ago
5

Samantha has 7/3 cups of ice cream to make milk shake.Each shake uses 1/8 cup of ice cream. How many milk shakes can she make?

Mathematics
1 answer:
Travka [436]2 years ago
7 0
18 milkshakes
Hope this helps

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What is the distance between the points (−7, 7) and (−7, 8) ? 1 unit 7 units 8 units 15 units Please Help I Will Mark Brainliest
k0ka [10]

√ 197

≈

14.03566884

So your answer should be 15 units

6 0
3 years ago
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Bob's Skate Shop had a profit of $3,563 during the month of August. The company models its profit using where x is the number of
CaHeK987 [17]

Answer:

The number of skateboard company sell during the month of August = 55

Step-by-step explanation:

We have given,

Profit function for Bob, P = x²+ 10x - 12

Bob's profit during August month is $3,563

That means, P = $3,563

We can use the profit formula given for Bob's profit:

P = x² + 10x - 12

Plug P =$3,563 in above formula.

i.e 3,563 = x² + 10x - 12

or 0 = x² + 10x -12 - 3,563

or 0 = x² + 10x - 3575

or x = 55, -65

Since number of skate boards can not be negative.

So we consider x= 55

Hence the number of skateboard company sell during the month of August = 55.

6 0
3 years ago
What diagram do I use???
lys-0071 [83]

Answer:

A Bar Graph

Step-by-step explanation:

This would be the best choice make the x axis the sports

and the y axis the numbers and make 2 bars for each sport one for girls one for boys

5 0
3 years ago
Consider the function f(x)=xln(x). Let Tn be the nth degree Taylor approximation of f(2) about x=1. Find: T1, T2, T3. find |R3|
Fynjy0 [20]

Answer:

R3 <= 0.083

Step-by-step explanation:

f(x)=xlnx,

The derivatives are as follows:

f'(x)=1+lnx,

f"(x)=1/x,

f"'(x)=-1/x²

f^(4)(x)=2/x³

Simialrly;

f(1) = 0,

f'(1) = 1,

f"(1) = 1,

f"'(1) = -1,

f^(4)(1) = 2

As such;

T1 = f(1) + f'(1)(x-1)

T1 = 0+1(x-1)

T1 = x - 1

T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2

T2 = 0+1(x-1)+1(x-1)^2

T2 = x-1+(x²-2x+1)/2

T2 = x²/2 - 1/2

T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3

T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3

T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)

Thus, T1(2) = 2 - 1

T1(2) = 1

T2 (2) = 2²/2 - 1/2

T2 (2) = 3/2

T2 (2) = 1.5

T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)

T3(2) = 4/3

T3(2) = 1.333

Since;

f(2) = 2 × ln(2)

f(2) = 2×0.693147 =

f(2) = 1.386294

Since;

f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).

Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,

Since;

f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2

Finally;

R3 <= |2/(4!)(2-1)^4|

R3 <= | 2 / 24× 1 |

R3 <= 1/12

R3 <= 0.083

5 0
3 years ago
What is the value of x in the equation −6 + x = −4? (1 point) a −10 b −2 c 2 d 10
Montano1993 [528]

Answer:

x = 2

Step-by-step explanation:

−6 + <em>x</em> = −4

<u>+6          +6</u>

       <em>x</em>  =  2

hope dis helps ^-^

6 0
3 years ago
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