1. false
2. false
3. true
Answer:
To find critical points, take the first derivative and set it equal to zero:
f(x) = -2x^2 + 4x + 5
f'(x) = -4x + 4
-4x+4 = 0
-4x = -4
x = 1
Critical point at x = 1
Alternatively, if you mean zeros, or where the x intersects, you can use the quadratic equation.
Answer: 35.3
Explanation: (-3-2-1+0+1+2+....27)/30 = 35.3
Answer:
-1<b<7, or i suppose b.
Step-by-step explanation:
6b<42
b<7
4b+12>8
4b>-4
b>-1
Answer:
23+12=
Step-by-step explanation:
you just need figure it out in your head and see what sounds right
