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yan [13]
2 years ago
8

A large offshore oil platform needs to transmit signals between different devices on the platform with high reliability and low

latency. However, they are unable to cover the platform with their existing Wi-Fi connections.What is the best solution for the platform in this scenario?
Computers and Technology
1 answer:
Brilliant_brown [7]2 years ago
6 0

This is based on getting a more efficient network.

<u><em>Best solution will be for them to install a private 5G connection on the platform</em></u><u>.</u>

<u> </u>

  • Now, we are told that they are not able to cover the platform with the Wi-Fi connections they are currently using.

Now, they need a connection that has high reliability and lower latency.

  • Now,  lower latency simply means there is little to no delay between the connection sending and receiving information. That means it can process a very high volume of data with very little delay. This indicates a very fast and efficient connection.

  • Since they are currently using Wi-Fi, it means they need something with a faster speed.

Wi-Fi could be 4G operates at around a frequency of 2.4GHz and speed of  while the one of 5G operates around 30 GHz.

  • Also, latency of 4G Wi-Fi is around 50 milliseconds while 5G is around 1 millisecond.

  • Also, the speed of 5G could be up to 20 GB per second which is almost 20 times more than that of 4G.

Thus, 5G is faster and also has a much lower latency than 4G Wi-Fi.

Thus, the best solution will be for them to install a private 5G connection on the platform.

Read more at; brainly.in/question/46252999

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Write a loop statement to count and display the number of positive integers in the array. That is, your loop should display the
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Answer:

int count =0;

    for(int i=0;i<10;i++)

    {

        if(myArray[i]>=0)

        {

            count++;

        }

    }

    cout<<"Number of positive integers is "<<count<<endl;

Explanation:

The above written loop is for counting positive integers in the myArray[].

For counting we have taken a count integer initialized with 0.On iterating over the array if the element is greater than or equal to 0 we consider it as positive and increasing the count.At the end printing the count.

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Is recursion ever required to solve a problem? What other approach can you use to solve a problem that is repetitive in nature?
Setler79 [48]

Answer:

No you can not tell that recursion is ever required to solve a problem.

Recursion is required when in the problem, the solution of the input depends on the solution of the subsets of the input.

Iteration is also another form of repetitive approach we follow to solve that kind of problems.

But the difference between recursion and iteration is :

  • In recursion we call the function repeatedly to return the result to next level.
  • In iteration certain bunch of instructions in a loop are executed until certain conditions met.

Explanation:

For example in the Fibonacci sequence problem, to find f_{n}, we need to compute f_{n-1} and f_{n-2} before that.

  • In case of recursion we just call the method Fibonacci(n) repeatedly only changing the parameter Fibonacci(n-1), that calculates the value and return it.

                           Fibonacci(n)

                           1. if(n==0 or n==1)

                           2.       return 1.

                           3.else

                           4.      return( Fibonacci(n-1)+Fibonacci(n-1) )

  • But in case of iteration we run a loop for i=2 to n, within which we add the value of current f_{i-1} and f_{i-2} to find the value of f_{i}

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                           1. if(n<=2)

                           2.    result = 1

                           3.     else

                           4. result1 =1 and result2=1.

                           5.      {  result = result1 +result2.

                           6.         result1= result2.

                           7.         result2 = result.

                           8.      }

                           9.  output result.

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