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lys-0071 [83]
3 years ago
9

Solve the system of inequalities 1-12y<:3y+1; 2-6y>4+4y

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
8 0

For 1 - 12y < 3y+1;        y > 15

For 2 - 6y  >  4  +  4y;   y  <  -0.2

The given inequalities are:

1  -  12y < 3y  +  1

2 - 6y  >  4  +  4y

For 1  -  12y < 3y  +  1:

1  -  12y < 3y  +  1

Collect like terms

-12y  -  3y  <  1  -  1

-15y    <   0

Multiply both sides by -1

-1(-15y)   >  0(-y)

15y    >   0

Divide both sides by 15

y   >  0/15

y   >   15

For 2 - 6y  >  4  +  4y

Collect like terms

-6y  - 4y  >  4  -  2

-10y   >   2

Multiply both sides by -1

-1(-10y)   <  2(-1)

10y   <  -2

y  <  -2/10

y  <  -0.2

Learn more here: brainly.com/question/11316045

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8 0
3 years ago
What is m∠PTQ???????????
anyanavicka [17]

Answer:

m∠PTQ = 40°

Step-by-step explanation:

From the picture attached,

Two lines PS and RQ are intersecting each other at a point T.

Vertical angles formed at the point of intersection T will be equal in measure.

m∠PTQ = m∠STR and m∠PTR = m∠QTS

Therefore, (x + 28)° = (2x + 16)°

28 - 16 = 2x - x

12 = x

m∠PTQ = (x + 28)°                            

             = 12 + 28

             = 40°

Therefore, measure of angle PTQ is 40°.

5 0
4 years ago
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Goryan [66]
Yes because they are constant throughout the table.
4 0
3 years ago
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7 0
3 years ago
I don’t understand how to do this problem
irga5000 [103]

Answer:

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Step-by-step explanation:

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3 0
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