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Taya2010 [7]
3 years ago
10

We use the properties of equality to rewrite equations and solve equations for a variable. These properties allow us to maintain

a balance between the two sides of the equation.
Why is it important to keep the two sides of an equation balanced when solving? What other properties do we use to rewrite expressions and equations?
Mathematics
1 answer:
bazaltina [42]3 years ago
3 0

Answer:

umm it's difficult I don't know‍♀️

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<img src="https://tex.z-dn.net/?f=71%20-%205x%20%3D%209x%20-%2013" id="TexFormula1" title="71 - 5x = 9x - 13" alt="71 - 5x = 9x
Sav [38]

You need to isolate x.


71 - 5x = 9x - 13

Add 13 to both sides.

84 - 5x = 9x

Add 5x to both sides.

84 = 14x

Divide both sides by 14.

6 = x


<h3>The answer is x = 6.</h3>
5 0
3 years ago
What would the answer be for this equation? 3a^3b^2x2a^2b^5
Wewaii [24]

9514 1404 393

Answer:

6a^5b^7

Step-by-step explanation:

The applicable rule of exponents is ...

  (a^b)(a^c) = a^(b+c)

__

It looks like you want to simplify ...

  3a^3b^2\times 2a^2b^5=(3\cdot2)a^{3+2}b^{2+5}=\boxed{6a^5b^7}

7 0
3 years ago
Read 2 more answers
Determine algebrically if f(x)=4x³-5x is odd or even function​
Gelneren [198K]

Answer:

Odd function

Step-by-step explanation:

So to see if a function is odd or even we need to plug in a negative x for x, so f(-x)=4(-x)^3-5(-x). This produces -4x^3+5x, which is the exact opposite of the original equation, so it is an odd function. If it were even, then the signs of the coefficients would be the same as the original function.

4 0
2 years ago
The sides of a rhombus with angle of 60° are 6 inches. Find the area of the rhombus.
ehidna [41]
1. Check the drawing of the rhombus ABCD in the picture attached.

2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.

3. The diagonals:
     i) bisect the angles so m(ODC)=60°/2=30°

     ii) are perpendicular to each other, so m(DOC)=90°

4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.

5. By the pythagorean theorem, DO= \sqrt{ DC^{2}- OC^{2} }=  \sqrt{ 6^{2}- 3^{2} }=\sqrt{ 36- 9 }=\sqrt{ 27 }= \sqrt{9*3}= 
=\sqrt{9}* \sqrt{3} =3\sqrt{3}  (in)

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*\frac{DO*OC}{2}=4 \frac{3 \sqrt{3} *3}{2}==2*9 \sqrt{3}=18 \sqrt{3} (in^{2})

6 0
3 years ago
Please help me I don't know how to do it
poizon [28]
Findd total collected
add everybody
fri+sat+sun+mon=
21+5 and 5/6+2.75+4 and 5/8
add what you can
21+5+2.75+4+5/6+5/8=
28.75+5/6+5/8
add the fractions by making denom same
5/6+5/8=20/24+15/24=35/24=1 and 9/24=1 and 3/8
28.75+1 and 3/8=29.75+3/8
that is how many barels total
times 205 since that is how many litesr in each bottle
205 times (29.75+3/8)=
205*29.75+205*(3/8)=
6098.75+76.875=
6175.625

29/30 is lost

1//30 remains
9175.625 times 1/30 (aka divided by 30)=205.854166666666666 litesr
205 bottles (and 0.85 partially full bottle)
3 0
3 years ago
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