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Taya2010 [7]
3 years ago
10

We use the properties of equality to rewrite equations and solve equations for a variable. These properties allow us to maintain

a balance between the two sides of the equation.
Why is it important to keep the two sides of an equation balanced when solving? What other properties do we use to rewrite expressions and equations?
Mathematics
1 answer:
bazaltina [42]3 years ago
3 0

Answer:

umm it's difficult I don't know‍♀️

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Which of the following could be points on the unit circle: A. (4/3, 4/5) B. (5/13, 12/13)
IRINA_888 [86]

Answer:

Option (2) and (4) are correct.

(\frac{5}{13},\frac{12}{13} ) and  (\frac{6}{7},\frac{\sqrt{13}}{7} ) are points on the unit circle.

Step-by-step explanation:

Given : Some points of circles.

We have to choose which points could be points on the unit circle.

We know, the equation of circle is

x^2+y^2=r^2  ..........(1)

where r is radius of circle.

We check each point for x and y values on the equation of circle and see which point gives radius = 1

Thus,

1) (\frac{4}{3},\frac{4}{5} )

Put  in LHS of  (1) , we have,

(\frac{4}{3})^2+(\frac{4}{5})^2

Simplify, we have,

=\frac{16}{9}+\frac{16}{25}

=\frac{544}{225}\neq 1

Thus,  (\frac{4}{3},\frac{4}{5} ) is not a point on the unit circle.

2) (\frac{5}{13},\frac{12}{13} )

Put  in LHS of  (1) , we have,

(\frac{5}{13})^2+(\frac{12}{13})^2

Simplify, we have,

=\frac{25}{169}+\frac{144}{169}

=\frac{169}{169}= 1

Thus, (\frac{5}{13},\frac{12}{13} ) is a point on the unit circle.

3) (\frac{1}{3},\frac{2}{3} )

Put  in LHS of  (1) , we have,

(\frac{1}{3})^2+(\frac{2}{3})^2

Simplify, we have,

=\frac{1}{9}+\frac{4}{9}

=\frac{5}{9}\neq 1

Thus,  (\frac{1}{3},\frac{2}{3} ) is not a point on the unit circle.

4)  (\frac{6}{7},\frac{\sqrt{13}}{7} )

Put  in LHS of  (1) , we have,

(\frac{6}{7})^2+(\frac{\sqrt{13}}{7})^2

Simplify, we have,

=\frac{36}{49}+\frac{13}{49}

=\frac{49}{49}= 1

Thus,  (\frac{6}{7},\frac{\sqrt{13}}{7} ) is a point on the unit circle.

Thus, (\frac{5}{13},\frac{12}{13} ) and  (\frac{6}{7},\frac{\sqrt{13}}{7} ) are points on the unit circle.

3 0
3 years ago
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Answer this question to get marked as barinliest!!!!
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Answer:

16.4in

Step-by-step explanation:

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I’m pretty sure the correct answer the teacher is looking for is B
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An equation is given.
stepladder [879]

Answer:

r = \sqrt{\frac{A}{4\pi } }

Step-by-step explanation:

Given

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\frac{A}{4\pi } = r² ( take the square root of both sides )

\sqrt{\frac{A}{4\pi } } = r

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