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Thepotemich [5.8K]
2 years ago
10

Write a program that will enable Tracy to draw one circle with a diameter of 50

Mathematics
1 answer:
e-lub [12.9K]2 years ago
8 0

Answer:

circle(50)

Step-by-step explanation:

The circle should have a diameter of 50 so the answer is simply "circle (50)"

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The standard coffee mug has a capacity of 16 fluid ounces
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1 cup is equal to 16 fl
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1. 1 1/2

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A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t
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Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field=1500000 square ft

Area of rectangular field=l\times b

Area of rectangular field=x\time y

1500000=xy

y=\frac{1500000}{x}

Fencing used ,P(x)=x+x+y+y+y=2x+3y

Substitute the value of y

P(x)=2x+3(\frac{1500000}{x})

P(x)=2x+\frac{4500000}{x}

Differentiate w.r.t x

P'(x)=2-\frac{4500000}{x^2}

Using formula:\frac{dx^n}{dx}=nx^{n-1}

P'(x)=0

2-\frac{4500000}{x^2}=0

\frac{4500000}{x^2}=2

x^2=\frac{4500000}{2}=2250000

x=\sqrt{2250000}=1500

It is always positive because length is always positive.

Again differentiate w.r.t x

P''(x)=\frac{9000000}{x^3}

Substitute x=1500

P''(1500)=\frac{9000000}{(1500)^3}>0

Hence, fencing is minimum at x=1 500

Substitute x=1 500

y=\frac{1500000}{1500}=1000

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used=2(1500)+3(1000)=6000 ft

Hence, the shortest length of fence that the rancher can used=6000 ft

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3 years ago
If the function f(x) = x^2 has the domain of 0,1,4,9 what is its range?
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The range for this function are 0,2,16,81

respectively

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