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tigry1 [53]
3 years ago
15

At what value of x do the graphs of the equations below intersect?

Mathematics
2 answers:
finlep [7]3 years ago
8 0
The intersection is the point where two equations meet. It is calculated by substituting terms into the equations involved. For the given systems of equation, calculations are as follows:

2x - y = 6
y = 2x - 6

We substitute the equation above to the second equation.

<span>5x + 10y = –10
</span>5x + 10(<span> 2x - 6</span> )= –10

Simplifying, 

5x + 20x - 60 = -10
25x = 50
x = 2

Therefore, the intersection has the value of x equal to 2.
Rashid [163]3 years ago
3 0

c (2) is the value in where the equations intersect

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Answer:

Angle = Ф = cos^{-1}(0) = 0

Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.

Step-by-step explanation:

Given vector r(t) = e^{t}cost i + e^{t}sint j

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As acceleration is velocity over time so:

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Implies that

vector a =

(e^{t}cost - e^{t}sint - e^{t}sint - e^{t}cost )i + ( e^{t}sint + e^{t}cost + e^{t}cost - e^{t}sint )j

vector a = (-2e^{t}sint) i + ( 2e^{t}cost)j

Now scalar product of position vector r and acceleration vector a:

r. a = . \\

r.a = -2e^{2t}sintcost + 2e^{2t}sintcost

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Now, for angle between position vector r and acceleration vector a is given by:

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Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.

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3 years ago
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