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Tom [10]
2 years ago
9

Write the verbal statement as an equation, using x for the variable.

Mathematics
1 answer:
viktelen [127]2 years ago
3 0

Complete question:

<em>Write the verbal statement as an equation using x as a variable. Then solve. 2 more than 3 times a number is 17. </em>

<em />

The required expression is 3x + 2 = 17 and the value of x is 5

Let the unknown number be x

  • 3 times a number is expressed as 3x
  • 2 more than3 times the number is 3x + 2

If the result is equivalent to 17, the required expression will be 3x + 2 = 17

Solve the resulting expression:

3x + 2 = 17

3x = 17 - 2

3x = 15

x = 15/3

x = 5

Hence the required expression is 3x + 2 = 17 and the value of x is 5

learn more here: brainly.com/question/14294864

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Lorne subtracted 6x3 – 2x + 3 from –3x3 + 5x2 + 4x – 7. Use the drop-down menus to identify the steps Lorne used to find the dif
Novay_Z [31]

Answer: Step 1: Reverse the signs of 6x^3-2x + 3 expression.

Step 2: Removing parenthesis

Step 3: Grouping like terms

Step 4: Combing like terms

Step 5: Writing the final expression in standard form

Step-by-step explanation: First expression :6x^3-2x + 3

Second expression : -3x^3+5x^2+4x-7.

We need to subtract 6x^3-2x + 3 from -3x^3+5x^2+4x-7.

Step 1: Reverse the signs of 6x^3-2x + 3 expression.

(-3x^3+5x^2+4x-7)+(-6x3+2x-3)

Step 2: Removing parenthesis

(-3x^3) +5x^2+4x + (-7) + (-6x^3) + 2x + (-3)

Step 3: Grouping like terms

[-3x^3) + (-6x^3)] + [4x + 2x] + [(-7) + (-3)] + [5x^2]

Step 4: Combing like terms

-9x^3 + 6x + (-10) + 5x^2

Step 5: Writing the final expression in standard form

-9x^3 + 5x^2 + 6x-10



8 0
3 years ago
Read 2 more answers
A clock was reading the time accurately on Friday at noon. On Monday at 6pm the clock was running late by 468 seconds. On averag
Setler [38]

The clock was skipping 3 seconds every 30 minutes from Friday noon to Monday 6 pm.

The clock was still accurate by Friday noon. The clock was late by 468 seconds by Monday, 6 pm.

To solve the problem, we must:

Know how many 30-minutes have passed during the time period.

1 day = 24 hours

1 hour = 60 minutes = 2 × (30 minutes)

1 day = 24 hours × 2 × (30 minutes)

1 day = 48 × (30 minutes)

Thus, there are 48, 30-minutes in a day. On Friday, however, we start counting at noon, which is half of the day. Moreover, on Monday, the mark is only up to 6 pm, which is three-fourths of the day.

Friday = 48 × \frac{1}{2} = 24

Saturday = 48

Sunday = 48

Monday = 48 × \frac{3}{4} = 36

TOTAL = 24 + 48 + 48 + 36 = 156

Therefore, the total number of 30-minutes that have passed is 156. There were 156, 30-minutes that passed during the time period.

Divide the number of total seconds late by the number of 30-minutes passed.

That is, the number of total seconds late= 468 seconds ÷ 156

= 3 seconds  

Therefore, the clock was skipping 3 seconds every 30 minutes from Friday noon to Monday 6 pm.

To learn more about clock problems visit:

brainly.com/question/27122093.

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3 0
2 years ago
Linda can bicycle 48 miles in the same time as it takes her to walk 12 miles. She can ride 9 mph faster than she can walk. How f
Marrrta [24]

Answer:

\frac{48}{r+9}=\frac{12}{r}

Step-by-step explanation:

Let r represent Linda's walking rate.                      

We have been given that Linda can ride 9 mph faster than she can walk, so Linda's bike riding rate would be t+9 miles per hour.

\text{Time}=\frac{\text{Distance}}{\text{Rate}}

We have been given that Linda can bicycle 48 miles in the same time as it takes her to walk 12 miles.

\text{Time while riding}=\frac{48}{r+9}

\text{Time taken while walking}=\frac{12}{r}

Since both times are equal, so we will get:

\frac{48}{r+9}=\frac{12}{r}

Therefore, the equation \frac{48}{r+9}=\frac{12}{r} can be used to solve the rates for given problem.

Cross multiply:

48r=12r+108

48r-12r=12r-12r+108

36r=108

\frac{36r}{36}=\frac{108}{36}

r=3

Therefore, Linda's walking at a rate of 3 miles per hour.

Linda's bike riding rate would be t+9\Rightarrow 3+9=12 miles per hour.

Therefore, Linda's riding the bike at a rate of 12 miles per hour.

7 0
3 years ago
If $7,000 is placed in an account with an annual interest rate of 5.5%, how long will it take the amount to triple if the intere
butalik [34]
A= P(1 + r/n) ^nt
21000=7000(1+0.055/2)^1t

t = 20.52 years

4 0
3 years ago
Use the elimination method to solve the system of equations. Choose the correct ordered pair.
kherson [118]
Make x=0 in the second equation, giving you y=-3. If you plug that in to the top equation you would get x-3(-3)=-19, x+9=-19,x=-28.
6 0
3 years ago
Read 2 more answers
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