We'll represent the distance as d and the time as t.
d= 3(t+7) because Gilda is 7 minutes late when travelling 3 mph
d= 4(t-5) because Gilda is 5 minutes early at 4 mph
d= 3t + 21
d= 4t -20
3t +21 =4t -20
41=t
d= 3(41) +21= 144
The distance is 144 miles.
The answer is 45 okay bro good
Answer:
The answer for your problem is 240
Step-by-step explanation:
A=wl=12·20=240
for this problem all you had to do was multiply
12*20 to get your answer
You can draw lines from the center of the hexagon to the peak. And you can find that this hexagon is divided to 6 parts. Every 60° can the hexagon map onto itself. So at 60,120,180,240,300 and 360 total 6 times.
The standard deviation of the frequency distribution is 5.54
<h3>How to determine standard deviation?</h3>
The table of values is given as:
x f(x)
0-3 13
4-7 13
8-11 10
12-15 11
16-19 0
20-23 3
Rewrite the table by calculating the class midpoints:
x f(x)
1.5 13
5.5 13
9.5 10
13.5 11
17.5 0
21.5 3
Start by calculating the mean using:

This gives

Evaluate

The standard deviation is then calculated as:

So, we have:

Evaluate

Solve

Hence, the standard deviation is 5.54
Read more about standard deviation at:
brainly.com/question/15858152
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