Answer:
PERIOD
Step-by-step explanation:
Answer:
n - (-6) < 9
n < 3
Step-by-step explanation:
When setting up an inequality, using the key words from the problem will help. The word 'difference' would indicate subtraction and 'less than' would be the '<' inequality sign. Since the expression is 'the difference of a number and -6', we write:
n - (-6) < 9
Whenever we subtract a negative number, we change both signs to positive:
n + 6 < 9
Using inverse operations to solve: n + 6 - 6 < 9 - 6
n < 3
Answer:
The answer is: y = 2/3x - 3
Step-by-step explanation:
Given point: (3, -1)
Given equation: y = 2/3x - 5, which is in the form y = mx + b where m is the slope and b is the y intercept.
Parallel lines have the same slope. Use the point slope form of the equation with the point (3, -1) and substitute:
y - y1 = m(x - x1)
y - (-1) = 2/3(x - 3)
y + 1 = 2/3x - 6/3
y + 1 = 2/3x - 2
y = 2/3x - 3
Proof:
f(3) = 2/3(3) - 3
= 6/3 - 3
= 2 - 3
= -1, giving the point (3, -1)
Hope this helps! Have an Awesome Day!! :-)
Answer:
P = 6200 / (1 + 5.2e^(0.0013t))
increases the fastest
Step-by-step explanation:
dP/dt = 0.0013 P (1 − P/6200)
Separate the variables.
dP / [P (1 − P/6200)] = 0.0013 dt
Multiply the left side by 6200 / 6200.
6200 dP / [P (6200 − P)] = 0.0013 dt
Factor P from the denominator.
6200 dP / [P² (6200/P − 1)] = 0.0013 dt
(6200/P²) dP / (6200/P − 1) = 0.0013 dt
Integrate.
ln│6200/P − 1│= 0.0013t + C
Solve for P.
6200/P − 1 = Ce^(0.0013t)
6200/P = 1 + Ce^(0.0013t)
P = 6200 / (1 + Ce^(0.0013t))
At t = 0, P = 1000.
1000 = 6200 / (1 + C)
1 + C = 6.2
C = 5.2
P = 6200 / (1 + 5.2e^(0.0013t))
You need to change the exponent from negative to positive.
The inflection points are where the population increases the fastest.
Answer:
Below.
Step-by-step explanation:
You find the values of y by substituting the values of x in the expression x^2 + 3x - 1.
So f(-4) = (-4)^2 + 3(-4) - 1 = 16-12-1 = 3
in the same way f(-3) = -1, f(-2) = -3, f(-1) = -3,
f(0) = -1 and f(1) = 3.
Now plot the points (-4, 3) , (-3, -1) and so on
Then you can read the values off this graph.
