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Elina [12.6K]
2 years ago
5

Evaluate 4+(m-n)^4 when m =7 and n = 5

Mathematics
1 answer:
Masja [62]2 years ago
6 0

Answer:

20.

Step-by-step explanation:

Plugging m = 7 and n = 5 into the given expression:

Answer = 4 + (7 - 5)^4

= 4 + 2^4

= 4 + 16

= 20.

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Prove that: 16sin20.sin40.sin60.sin80=3​
olga nikolaevna [1]

to prove that 6720. Sin 40. Sin 60. 80 equals 3 you'd have to divide 16 by 20 multiply subtract both sides by 3 which is 24x + 6x + 8x + -14 equals 40 40 + 20 equals 16 - -40 equals 80 which equals to 3

6 0
4 years ago
How do you do this??
Nana76 [90]

Answer:

A-2, B-5, C-1, D-6, E-3, F-4

Step-by-step explanation:

The A would be the function x^3, so it would be the volume of a cube which is #2

B is probably the temperature graph, because it is warmest in the middle of the day and cooler at both ends, so that is #5

C is probably the age of an oak tree because it starts at 0, and grows linearly. #1

E is #3 because it is decreasing and so is the fuel in the tank.

F is the area of a triangle one, because that would be a quadratic function (half of a parabola)#4

D is the car wash, it doesn't start at 0 because the x-axis is the time of day. #6




6 0
3 years ago
2x-3y=4<br> -4x+6y=-8. <br> solve by elimination
oksano4ka [1.4K]
2x-3y=4 \\&#10;-4x+6y=-8 \ \ \ |\div 2 \\ \\&#10;2x-3y=4 \\&#10;\underline{-2x+3y=-4} \\&#10;2x-2x-3y+3y=4-4 \\&#10;0=0 \\ \\&#10;\boxed{\hbox{infinitely many solutions}}
4 0
3 years ago
Read 2 more answers
A bottle of chocolate syrup says to mix 2 ounces of syrup with 8oz. of milk. If the bottle contains 32 ounces of syrup, how much
Vikki [24]

Answer:

128oz

Step-by-step explanation:

Ratios!

2oz syrup:8ozmilk

which simplifies to:

1oz syrup:4milk

32oz syrup: 4(32)milk

128oz. milk

3 0
2 years ago
20 POINTS!!! Use the quadratic formula above to solve for h(t) = -4.9t^2 + 8t + 1 where h is the height of the ball in meters an
Elina [12.6K]

Answer:

Two solutions: -0.12 and 1.75.

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}. Assuming that the x² term is a, the x term is b, and the constant is c, we can plug the values into the equation.

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {8^2 - 4\cdot-4.9\cdot1} }}{{2\cdot-4.9}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {64 + 19.6} }}{{-9.8}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {83.6} }}{{-9.8}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {9.14} }}{{-9.8}}} \end{array}

\frac{-8 + 9.14}{-9.8} = -0.12

\frac{-8-9.14}{-9.8} =1.75

Hope this helped!

3 0
3 years ago
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