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3 years ago

How many units is -1 + (-3) from -1?

Mathematics

1 answer:

Agata [3.3K]3 years ago

8 0

$-1+(-3)$ is 3 units from $-1$

Explanation:

To find distance between two points always take absolute value.

$-1+(-3)=-1-3\\=-4$

So, to find how many units -4 from -1 is,

$-1-(-4)=-1+4\\ = 3 units$

Learn more:

brainly.com/question/12928519

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gogolik [260]

They had 20:2 point problems. They also had 20:5 point problems.

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4 years ago

"A supplier of digital memory cards claims that no more than 1% of the cards are defective. In a random sample of 600 memory car

Nady [450]

Answer:

Both the values fall in the critical region so we reject H0: p ≤ 0.01 and conclude that the results are significantly different from chance identification and it is not a sample fluctuation.

Step-by-step explanation:

1) Formulate the hypothesis

H0: p ≤ 0.01 against the claim Ha: p > 0.01

2) Choose the significance level ∝= 0.01

3) The test statistics under H0 is

z= x -np /√npq ( without continuity correction)

z= x ± 1/2 -np /√npq ( with continuity correction)

4) the critical region is z> ±2.33 because the alternate hypothesis is stated on greater than basis.

5)Computations:

Z= x -np /√npq ( without continuity correction)

Z= 6- 600( 0.03)/√ 600( 0.03)(0.97)

z= - 2.82 ( without continuity correction)

z= x ± 1/2 -np /√npq ( with continuity correction)

Z= (6-0.5)- 600( 0.03)/√ 600( 0.03)(0.97)

z= -12.5/4.1785

z= -0.29915 ( with continuity correction)

6) Both the values fall in the critical region so we reject H0: p ≤ 0.01 and conclude that the results are significantly different from chance identification and it is not a sample fluctuation.

8 0

3 years ago

Consider the probability that greater than 77 out of 131 computers will crash in a day. Assume the probability that a given comp

sweet-ann [11.9K]

Answer:

A Normal approximation to binomial cannot be applied to approximate the distribution of X, the number of computer crashes in a day.

Step-by-step explanation:

Let X = number of computers that will crash in a day.

The probability of a computer crashing in a day is, p = 0.99.

A random sample of n = 131 is selected.

A random computer crashing in a day is independent of the others.

The random variable X follows a Binomial distribution with parameters n = 131 and p = 0.99.

But the sample size is quite large, i.e. n > 30.

So the distribution of X can be approximated by the normal distribution if the following conditions are fulfilled:

np ≥ 10
n(1 - p) ≥ 10

Check whether the conditions satisfy or not:

$np=131\times 0.99=129.69>10\\n(1-p)=131\times (1-0.99)=1.31$

The second condition is not fulfilled.

A Normal approximation to binomial cannot be applied to approximate the distribution of X, the number of computer crashes in a day.

6 0

3 years ago

(25 POINTS) For 10 grams of a radioactive sample of carbon-14, which has a half life of 5730 years, write an equation to model h

natima [27]

Answer:

I think it is D.

Step-by-step explanation:

3 0

3 years ago

Un equipo de futbol esta compuesto por 13 personas, contando el entrenador y el masajista. Tras jugar un partido, reciben para t

AleksandrR [38]

Answer:

Ok, tenemos que el cheque es de 16_41.

Y también sabemos que podemos dividir este numero entre 13 personas, de acá podemos concluir que este numero es un múltiplo de 13.

Sea el dígito faltan igual a x

Sabemos que un numero es divisible por 13 cuando la suma de los productos de las unidades, decenas, centenas,... De dicho número por los dígitos contenidos en la lista {1, –3, –4, –1, 3, 4 } (en ese orden) es 0 o múltiplo de 13.

Entonces, tenemos:

16x41:

1*1 + 4*(-3) + x*-4 + 6*-1 + 1*3 = 1 - 12 -4x - 6 + 3

=-14 - 4*x

entonces, -14 - 4*x tiene que ser igual a 0, 13 o algún múltiplo de 13.

Como ambos términos son negativos, no podemos tener esta igualdad igual a 0 o a 13, entonces apuntamos por el siguiente múltiplo de 13 después de -13 (es decir, 13*-2 = -26)

-26 = -14 - 4*x

-26 + 14 = -4*x

-12 = -4*x

-12/-4 = 3 = x

Entonces nuestro dígito es igual a 3, y nuestro numero es:

16341.

Ahora podemos probar:

16241/13 = 1257

Es decir, cada miembro recibe 1257.

6 0

4 years ago