The Rotokas of Papua New Guinea have twelve letters in their alphabet. The letters are: A, E, G, I, K, O, P, R, S, T, U, and V.
Mnenie [13.5K]
12 letters in all but less "S" which is not allowed. That leave 11 usable letters, of which 5 distinct letters are used for each plate.
begins with G or K (2 choices). That leaves 10 letters.
Ends with T (1 choice). That least 9 for the middle letters.
Second letter (9 choices)
Third letter (8 choices)
Fourth letter (7 choices)
Total number of licence plates
=product of choices of letters for each position
= 2*9*8*7*1
=1008
Since the area of any thing is length time width, we can divide 4864 by 152 to get the width of the garden. This gives us 32. Now we need to add 152 + 152 + 32 + 32 to get our total feet of fencing necessary. This would give us 368 feet of fencing.
Answer:
4/5
Step-by-step explanation:
Common factor is 3 so,
if you divide 12/15 by 3, then it will equal to 4/5
Answer:
Step-by-step explanation:
a.
first number is 1000-1+9=1008
9)1000(1
9
-------
10
9
-----
10
9
----
1
----
last number is 9999
9| 9999
---------
1111 |0
--------
9999=1008+(n-1)9
9999-1008=(n-1)9
n-1=8991/9=999
n=999+1=1000
b.
first digit=1000
last digit=9999-1=9998
2 |9999
---------
|4999|1
9998=1000+(n-1)2
(n-1)2=9998-1000=8998
n-1=4499
n=4499=1=5000
c.not sure
d.
total numbers=9000
9999=1000+(n-1)1
9999-1000=n-1
n=8999+1=9000
numbers divisible by 3=3000
first number=1002
last number=9999
9999=1002+(n-1)3
(n-1)3=9999-1002=8997
n-1=2999
n=2999+1=3000
numbers not divisible by 3=9000-3000=6000
e.
numbers divisible by 5=1800
first number=1000
last number=9995
9995=1000+(n-1)5
(n-1)5=9995-1000=8995
n-1=1799
n=1799+1=1800
numbers divisible by 7=1286
7 | 1000
---------
| 142-6
1000-6+7=1001
7 | 9999
|---------
1428-3
9999-3=9996
first digit=1001
last digit=9996
9996=1001+(n-1)7
(n-1)7=9996-1001=8995
n-1=1285
n=1285+1=1286
numbers divisible by 35=257
first digit=1015
35 ) 1000 ( 28
70
----
300
280
------
20
---
1000-20+35=1015
35)9999(285
70
----
299
280
-----
199
175
----
24
----
last digit=9999-24=9975
9975=1015+(n-1)35
(n-1)35=9975-1015=8960
n-1=8960/35=256
n=257
reqd. numbers=1800+1286-257=3019
If 1 line completely overlaps the other line, they are the same line with infinite solutions.....so ur answer would be the 4th one