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lidiya [134]
2 years ago
10

Help me with this please

Mathematics
1 answer:
Pavel [41]2 years ago
5 0

bro

Step-by-step explanation:

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The Rotokas of Papua New Guinea have twelve letters in their alphabet. The letters are: A, E, G, I, K, O, P, R, S, T, U, and V.
Mnenie [13.5K]

12 letters in all but less "S" which is not allowed. That leave 11 usable letters, of which 5 distinct letters are used for each plate.

begins with G or K (2 choices). That leaves 10 letters.

Ends with T (1 choice). That least 9 for the middle letters.

Second letter (9 choices)

Third letter (8 choices)

Fourth letter (7 choices)

Total number of licence plates

=product of choices of letters for each position

= 2*9*8*7*1

=1008

3 0
3 years ago
Miles is putting a fence around his garden. The total area of the garden is 4,864 square feet. The length of the garden is 152 f
JulsSmile [24]
Since the area of any thing is length time width, we can divide 4864 by 152 to get the width of the garden. This gives us 32. Now we need to add 152 + 152 + 32 + 32 to get our total feet of fencing necessary. This would give us 368 feet of fencing.
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3 years ago
Write th fraction 12/15 in its simpliest form​
kolbaska11 [484]

Answer:

4/5

Step-by-step explanation:

Common factor is 3 so,

if you divide 12/15 by 3, then it will equal to 4/5

4 0
3 years ago
Read 2 more answers
How many positive integers between 1000 and 9999 inclusive
bekas [8.4K]

Answer:

Step-by-step explanation:

a.

first number is  1000-1+9=1008

9)1000(1

    9

-------

     10

       9

    -----

       10

         9

       ----

         1

       ----

last number is 9999

9| 9999

  ---------

    1111 |0

    --------

9999=1008+(n-1)9

9999-1008=(n-1)9

n-1=8991/9=999

n=999+1=1000

b.

first digit=1000

last digit=9999-1=9998

2 |9999

  ---------

  |4999|1

9998=1000+(n-1)2

(n-1)2=9998-1000=8998

n-1=4499

n=4499=1=5000

c.not sure

d.

total  numbers=9000

9999=1000+(n-1)1

9999-1000=n-1

n=8999+1=9000

numbers divisible by 3=3000

first number=1002

last number=9999

9999=1002+(n-1)3

(n-1)3=9999-1002=8997

n-1=2999

n=2999+1=3000

numbers not divisible by 3=9000-3000=6000

e.

numbers divisible by 5=1800

first number=1000

last number=9995

9995=1000+(n-1)5

(n-1)5=9995-1000=8995

n-1=1799

n=1799+1=1800

numbers divisible by 7=1286

7 | 1000

  ---------

  |  142-6

1000-6+7=1001

7 | 9999

  |---------

    1428-3

9999-3=9996

first digit=1001

last digit=9996

9996=1001+(n-1)7

(n-1)7=9996-1001=8995

n-1=1285

n=1285+1=1286

numbers divisible by 35=257

first digit=1015

35 ) 1000 ( 28

        70

       ----

        300

        280

        ------

           20

           ---

1000-20+35=1015

35)9999(285

     70

    ----

     299

     280

     -----

        199

        175

        ----

          24

         ----

last digit=9999-24=9975

9975=1015+(n-1)35

(n-1)35=9975-1015=8960

n-1=8960/35=256

n=257

reqd. numbers=1800+1286-257=3019

7 0
3 years ago
Suppose that when a system of linear equations is graphed, one line completely overlaps the other line. Which statement is corre
N76 [4]
If 1 line completely overlaps the other line, they are the same line with infinite solutions.....so ur answer would be the 4th one
6 0
3 years ago
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