The first answer is 3/34 sec and the second answer is 15/34 sec.
Set up a proportion for these problems. For the first question,
340/1 = 30/x
Cross multiply:
340*x = 1*30
340x = 30
Divide both sides by 340:
340x/340=30/340
x = 30/340 = 3/34
For the second question,
340/1 = 150/x
Cross multiply:
340*x = 150*1
340x=150
Divide both sides by 340:
340x/340 = 150/340
x = 150/340 = 15/34

As per given in question, T is mid - point of QP ; so the measures QT and TP are equal.
that is :



Value of x is 6, so correct choice is D
Answer:
its b The angles need to add up to 90 degrees and this fits the formula
The answer of this is true
<h3>
Answer: Choice A) 0.20</h3>
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Explanation:
Let's say there are 1000 students. The students must take math, science or they can take both simultaneously.
- 65% of them are in math. So there are 0.65*1000 = 650 math students.
- 43% are in science, leading to 0.43*1000 = 430 science students.
- 13% are in both so we have 0.13*1000 = 130 students who are in both.
Now onto the sentence that says "Suppose a high school student who is enrolled in a math class is selected at random"
This means we only focus on the 650 math students and ignore the 1000-650 = 350 students who aren't in math.
Of those 650 math students, 130 are also in science (since 130 are in both classes).
The probability we're after is therefore 130/650 = 0.20