“The breaking distance is directly proportional to the square of its speed”
Using your variables, this means: d = k•b^2
k here is some unknown (and for this question irrelevant) number.
Now if b (the speed) is increased by 200%, then your new speed is b+2b = 3b. The 2b is the 200% increase.
Throw 3b into the first equation we have the new d as:
d = k • (3b)^2
Simplifying this, you have d = k•9b or d=9kb
This means the new braking distance is 9 times the original braking distance.
It would 20.5, but rounded off would be 21
Answer:
0.20%
Step-by-step explanation:
Answer:
Explanation:
<u>Given Expression</u>:
Use the Quadratic Formula:
<u>insert coefficients</u>
i dont no 44444 but thanks for the points
