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expeople1 [14]
3 years ago
9

How does the graph of a system of equations with one solution differ from the graph of a system of equations with infinitely man

y solutions or no solution?
Mathematics
1 answer:
Tresset [83]3 years ago
5 0

Answer:

To solve a system of linear equation graphically, it is best to write both equations in slope-intercept form first. After you put them in slope-intercept form, you should be able to graph them easily.For one solution, the two lines have to intersect at exactly one point, since both equations are satisfied at the intersection.

For no solution, the two lines have to never intersect, which means they have to be parallel lines. In other words, no solution will satisfy both equation.

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Simplify the expression -3.7 + 5g + 4k + 11.1 + (-10g)
Ede4ka [16]
I believe the answer would be
7.4 - 5g + 4k
3 0
3 years ago
If f(1)=2f(1)=2 and f(n)=f(n-1)^2-n
katrin [286]

Answer:

f(4)=-3

Step-by-step explanation:

f(1)=2

f(n)=f(n-1)^2-n

If n=2

f(2)=f(2-1)^2-2

f(2)=f(1)^2-2

f(2)=2^2-2

f(2)=4-2

f(2)=2

If n=3

f(3)=f(3-1)^2 - 3

f(3)=f(2)^2 - 3

f(3)=2^2-3

f(3)=4-3

f(3)=1

if n=4

f(4)=f(4-1)^2 - 4

f(4)=f(3)^2 - 4

f(4)=1^2 - 4

f(4)=1-4

f(4)=-3

6 0
3 years ago
What the product to (-3q+3)+7(8q+1)
Ivenika [448]

Answer:

53q+10

Step-by-step explanation:

(-3q+3)+7(8q+1)

-3q+3+56q+7

53q+3+7

53q+10

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!!!!!!!!!! answer the picture below
Nat2105 [25]
The answer to this is (4,0)
6 0
3 years ago
Read 2 more answers
Beatrice calculated the slope between two pairs of points.
kumpel [21]

Answer:

The answer in the procedure

Step-by-step explanation:

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope between (-3, -2) and (1, 0)

m=\frac{0+2}{1+3}

m=\frac{2}{4}=\frac{1}{2}

Find the equation of the line

y-y1=m(x-x1)

with m and the point (1,0)

substitute

y-0=\frac{1}{2}(x-1)

y=\frac{1}{2}x-\frac{1}{2}

step 2

Find the slope between (-2, -1) and (4, 2)

m=\frac{2+1}{4+2}

m=\frac{3}{6}=\frac{1}{2}

Find the equation of the line

y-y1=m(x-x1)

with m and the point (4,2)

substitute

y-2=\frac{1}{2}(x-4)

y=\frac{1}{2}x-2+2

y=\frac{1}{2}x

<em>Compare the equation of the two lines</em>

The two lines are parallel, because their slope is the same, but are different lines

therefore

Beatrice's conclusion is incorrect

All of these points are not on the same line, because are different parallel lines

The slope between (-2,-1) and (1,0) is equal to \frac{1}{2}

8 0
3 years ago
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