There are 5 different coloured cups in a row.
1 answer:
There are 12 possible arrangements.
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- Considering that the blue cup has to be on one end, we consider the number of arrangements possible with the other 4 cups, then multiply by 2(considering the blue on each end).
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- Considering green and yellow before red and purple, there are
outcomes(G-Y-R-P, G-Y-P-R, Y-G-R-P and Y-G-P-R).
- Another two possible outcomes are yellow-purple and green-red, or vice-versa, thus 4 + 2 = 6 outcomes.
- To account for the blue on the end, multiplying by 2.
- There are 12 possible arrangements.
A similar problem is given at brainly.com/question/24617788
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Answer:
The company should promote a lifetime of 3589 hours so only 2% burnout before the claimed lifetime
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What lifetime should the company promote for these bulbs, whereby only 2% burnout before the claimed lifetime?
This is the value of X when Z has a pvalue of 0.02. So it is X when Z = -2.055.
The company should promote a lifetime of 3589 hours so only 2% burnout before the claimed lifetime