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3 years ago

Could someone pkease help. i am not sure if i have the correct answer, thanks

Mathematics

1 answer:

Mama L [17]3 years ago

5 0

I believe you are correct keep it up

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∠1 and ∠2 are supplementary.

ad-work [718]

Supplementary means the 2 angles add up to 180 so...

124+(2x+4)=180

124+2x+4=180

124+2x+4-4=180-4

124+2x=176

124-124+2x=176-124

2x=52

2x/2=52/2

x=26
plug in and check

124+2x+4=180

124+2 (26)+4=180

124+52+4=180

176+4=180

180=180

6 0

3 years ago

A square has a side that is (x-3) units long. If the area of the square is 126.5625 sq units, what is the value of x?

Kitty [74]

Answer:

14.25 units

Step-by-step explanation:

Area of a square= $l*b= (x-3)(x-3)=x^{2}-3x-3x+9=x^{2}-6x+9$

$x^{2}-6x+9=126.5625$

$x^{2}-6x-117.5625$

Solving the equation using quadratic equation then as attached

x=14.25 units

To prove

x-3=14.25-3= 11.25 units

area=11.25*11.25=126.5625 sq units

4 0

3 years ago

The answer and the work that was needed to solve it .

cupoosta [38]

First, you add up all the prices. 1.79 + 2.99 + 4.37 + 0.33 = 9.48. Then, you do 10.00 - 9.48 = 0.52 and that's your answer.

7 0

3 years ago

Read 2 more answers

In the diagram which two angles are corresponding angles with angle 12?

Aleks04 [339]

Corresponding angles:
8< and <16

hope it helps

4 0

3 years ago

Read 2 more answers

Section 5.2 Problem 6: Find the general solution <img src="https://tex.z-dn.net/?f=y%27%27%20%2B%206y%27%20%2B%2010y%2

mihalych1998 [28]

Answer:

$y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Step-by-step explanation:

Given Second-Order Homogenous Differential Equation

$y''+6y'+10y=0$

Use Auxiliary Equation

$m^2+6m+10=0\\\\(m+3)^2+1=0\\\\(m+3)^2=-1\\\\m+3=\pm i\\\\m=-3\pm i$

General Solution

$y=e^{pt}(A\: cos\: qt+B\:sin\:qt)\\\\y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Note that the DE has two distinct complex solutions $p\pm qi$ where $A$ and $B$ are arbitrary constants.

4 0

2 years ago