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zhuklara [117]
3 years ago
6

READ QUESTION CAREFULLY, PLS ANSWER WITH WORKING

Mathematics
1 answer:
kotykmax [81]3 years ago
4 0

Expressions for 'c' and 'd' in terms of 'a' will be (d=4a) and (c=a^2+8).

  In question number 12, it's given that (a+\sqrt{8})^2 can be written as (c+d\sqrt{2}).

So the expression representing the situation will be,

(a+\sqrt{8})^2=(c+d\sqrt{2})

Now simplify the expression,

a^2+8+2a\sqrt{8}=c+d\sqrt{2}

(a^2+8)+2a\sqrt{8}=(c+d\sqrt{2})

(a^2+8)+4a\sqrt{2}=(c+d\sqrt{2})

Compare both the sides of the equation,

c=a^2+8

4a\sqrt{2}=d\sqrt{2}

d=4a

    Therefore, (d=4a) and (c=a^2+8) will be the expressions for c and d in terms of a.

Learn more,

brainly.com/question/13030227

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f(x)=\dfrac{1}{6}x+12\to y=\dfrac{1}{6}x+12


Change x to y, and y to x.


x=\dfrac{1}{6}y+12


solve for y:


\dfrac{1}{6}y+12=x\ \ \ |-12\\\\\dfrac{1}{6}y=x-12\ \ \ \ |\cdot6\\\\y=6x-72


Your answer is:


f^{-1}(x)=6x-72

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C

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