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zhuklara [117]
3 years ago
6

READ QUESTION CAREFULLY, PLS ANSWER WITH WORKING

Mathematics
1 answer:
kotykmax [81]3 years ago
4 0

Expressions for 'c' and 'd' in terms of 'a' will be (d=4a) and (c=a^2+8).

  In question number 12, it's given that (a+\sqrt{8})^2 can be written as (c+d\sqrt{2}).

So the expression representing the situation will be,

(a+\sqrt{8})^2=(c+d\sqrt{2})

Now simplify the expression,

a^2+8+2a\sqrt{8}=c+d\sqrt{2}

(a^2+8)+2a\sqrt{8}=(c+d\sqrt{2})

(a^2+8)+4a\sqrt{2}=(c+d\sqrt{2})

Compare both the sides of the equation,

c=a^2+8

4a\sqrt{2}=d\sqrt{2}

d=4a

    Therefore, (d=4a) and (c=a^2+8) will be the expressions for c and d in terms of a.

Learn more,

brainly.com/question/13030227

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3 years ago
3x^2 + 4x = -8<br> solve using quadratic formula
Firdavs [7]

Use the quadratic equation to solve this (image of the quadratic equation is below)

Remember that quadratic functions are set up like so:

ax^{2} +bx +c = 0

To make the equation 3x² + 4x = -8 into a quadratic function you must bring -8 to the left side of the equation so it equals zero. To do this add 8 to both sides

3x² + 4x + 8= -8 + 8

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\frac{-4+/-\sqrt{(4)^{2}-4(3)(8)}}{2(3)}

\frac{-4+/-\sqrt{16-96}}{6}

\frac{-4+/-\sqrt{-80}}{6}

^^^There is no real solution to this equation. You must have an imaginary solution

\frac{-4+/-i\sqrt{80}}{6}

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Hope this helped!

~Just a girl in love with Shawn Mendes

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3 years ago
I need the answers for this please
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Step-by-step explanation:

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Answer:

12

Step-by-step explanation:

Given: Diagonal of square= 3\sqrt{2}

To find the perimeter of square, we need to find the length of sides of square.

∴ Using the formula of diagonal to find side of square.

Formula; Diagonal= s\sqrt{2}

Where, s is side of square.

⇒ 3\sqrt{2} = s\sqrt{2}

Dividing both side by √2

⇒s= \frac{3\sqrt{2} }{\sqrt{2} }

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Hence, Length of side of square is 3.

Now, finding the perimeter of square.

Formula; Perimeter= 4s

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∴ Perimeter= 12

Hence, Perimeter of square is 12.

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