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Serga [27]
3 years ago
6

16:12 give the answer as n:1

Mathematics
1 answer:
Helen [10]3 years ago
7 0

Answer:

1\frac{1}{3} : 1

Step-by-step explanation:

they are both divisible by 4 so you divide. You will get 4:3. Since you wanted n:1 , you have to divide both sides by 3. the answer is  1\frac{1}{3} : 1

If this helped, please mark me as brainliest, thank you!

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CATIVO
yKpoI14uk [10]

Answer:

La cantidad de dinero adeuda al final de los dos procesos es $1450

Step-by-step explanation:

Los parámetros del proceso son;

La cantidad ahorrada para comprar ropa = $2,000

La cantidad pagada por la ropa = $2600

La cantidad prestada a un amigo = $650

La cantidad adeuda por teléfono celular durante 3 meses = $250

Deje que 'C', represente la suma de las transacciones anteriores, tenemos;

∴ C = 2,000 - 2,600 - 650 - 200 = -1,450

La suma de las transacciones anteriores, C = -$1,450

Por lo tanto, al final de los dos procesos, la cantidad de dinero adeuda es C = $1,450

-

3 0
3 years ago
The number of students at Lala High School is 64 less than 3 times the number of students at Banana High School. Which expressio
dangina [55]

Answer:

3s - 64

Step-by-step explanation:

7 0
3 years ago
A man has 16 coins in his pocket, all of which are nickels and quarters. If the total value of his change is $1.40, how many of
salantis [7]

Answer:

3 quarters 13 nickels

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Are any of these functions?
Kaylis [27]

Answer:

No, they are not.

Step-by-step explanation:

The easiest way to find a function on a graph is by finding if any points share the same x value. All of these do, so none are functions.

3 0
3 years ago
0.5 is 30 minutes how do I work out more times e.g. How many minutes is 0.45 or 0.48 I don't know how to do it help
kompoz [17]
I dont know if this will help you, but a 15th (.15) of an hour is 9 minutes!
So it'd be
.15=9 minutes
.30=18 minutes
.45=27
.60=36
.75=45 
.90=54
and obviously
1.0 is 60 minutes
(((EVERY .05 IS THREE MINUTES))))
3 0
3 years ago
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