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Zigmanuir [339]
3 years ago
15

Please help with this.

Mathematics
2 answers:
Klio2033 [76]3 years ago
5 0

Answer:

5-10 then6-12 because it goes by 2

r-ruslan [8.4K]3 years ago
5 0
Y= 1/2 or .5 due to the fact the cost times either of these numbers equals y.

Answer is .5y=1x
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The Forest family watched television for a total of
r-ruslan [8.4K]
Show me the full question
3 0
4 years ago
1. How many fourteenths are in 5/14?
never [62]

....... argue 6e73t83hwp260wcsihwoec

6 0
3 years ago
PLEASE SOMEONE HELP ASAP AND SHOW THE WORK
julsineya [31]
The sum of two sides of a triangle must be greater than the third side
1) 5+9>14
14>14 It is incorrect so you can’t have these lengths

2)7+7>15
14>15 X

3)1+2>4
3>4 X

4)3+6>8
9>8

6+8>3
14>3

8+3>6
11>6

So the fourth choice is correct
8 0
3 years ago
Find the solutions of each equation on the interval [0, 2π). si (3pi/2+x)+ sin (3pi/2+x)=-2
ANEK [815]

Answer:

The solutions are 0° and 3π

Step-by-step explanation:

On solving the equation given;

sin(\frac{3\pi}{2}+x )+ sin(\frac{3\pi}{2}+x ) = -2\\2sin(\frac{3\pi}{2}+x ) = -2\\sin(\frac{3\pi}{2}+x ) = -1\\\frac{3\pi}{2}+x  = sin^{-1}-1\\ \frac{3\pi}{2}+x = -\frac{\pi}{2} \\x = -\frac{\pi}{2} -\frac{3\pi}{2} \\x =  \frac{-4\pi}{2} \\x = -2\pi\\

<u>Since sin is negative in the 3rd and 4th quadrant, </u>

In the 3rd quadrant;

x =180°+2π

x = π + 2π

x = 3π

In the 4th quadrant;

x = 360°-2π

x = 2π-2π

x = 0°

6 0
3 years ago
Where is the center of the largest circle that you could draw inside a given triangle? . A.the point of concurrency of the media
juin [17]

The <em><u>correct answer</u></em> is:

C.the point of concurrency of the angle bisectors of the triangle

Explanation:

The largest circle that can be drawn inside a triangle is called an inscribed circle.  The center of this circle is called the incenter.

The incenter is formed by the intersection of the angle bisectors of all 3 angles in the triangle.

5 0
3 years ago
Read 2 more answers
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