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3 years ago

Please help with this.

Mathematics

2 answers:

Klio2033 [76]3 years ago

5 0

Answer:

5-10 then6-12 because it goes by 2

r-ruslan [8.4K]3 years ago

5 0

Y= 1/2 or .5 due to the fact the cost times either of these numbers equals y.

Answer is .5y=1x

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solong [7]

Answer:

98 inches

Step-by-step explanation:

Multiply the top length by the bottom length

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2 years ago

Can someone help me please

defon

Answer:

181.25 square feet

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Step-by-step explanation:

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3 years ago

Пожалуйста помогите с решением

zubka84 [21]

Answer:

( x, y) =

$65 \ \frac{15}{11}$

this is your answer

3 0

2 years ago

Which expression is equal to 4√32 • √2<br> A. 16<br> B. 4√2<br> C. 32<br> D. 16 √2

Georgia [21]

the is c.32$&$&#&#

Step-by-step explanation:

&&&&

4 0

3 years ago

Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago