We take the equation
<span>x^2 -4x + y^2 + 6y + 12 = 0
and complete the square for x and y.
</span><span>x^2 -4x + 4 - 4 + y^2 + 6y + 9 - 9 + 12= 0</span>
<span> (x-2)^2 - 4 + (y+3)^2 - 9 = -12</span>
<span> <span>(x-2)^2+ (y+3)^2 = 1
Therefore the answer is </span></span><span>(x-2)^2+ (y+3)^2 = 1</span>
Answer:
The correct answer is whole
