Triangle EFG can also be proven to be a right triangle by using the following: D. Prove that KL is equal to c by Pythagorean Theorem.
<h3>What is the Pythagorean Theorem?</h3>
The Pythagorean theorem states that the square of the longest side of a right triangle, which is the hypotenuse (c²) equals the sum of the squares of the other two legs of the right triangle (a² + b²).
If we apply the Pythagorean theorem, we would find the length of KL. If KL has the same length as c in triangle EFG, then we can say that triangle EFG is also a right triangle.
Therefore, the answer is: D. Prove that KL is equal to c by Pythagorean Theorem.
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Answer:
y = -2x + 1.
Step-by-step explanation:
2y = x - 1
y = 1/2y - 1/2
If line X is perpendicular to line Y (the line where y = 1/2y - 1/2), the slope will be the negative reciprocal of line Y. That means that there will be a negative sign instead of positive, and the 1/2 will be flipped to become 2/1, which is 2.
So, the slope will be -2.
We now have y = -2x + c.
To find c, simply put in -1 for x and 3 for y.
3 = -2 * -1 + c
c + 2 * 1 = 3
c + 2 = 3
c = 1
So, the equation of the line is y = -2x + 1.
Hope this helps!
Answer:
The answer is fifteen because 24 divided by 8 is 3 and 5 x 3 is 15
Answer:
Distance to the xy-plane = |z|
Distance to the yz-plane = |x|
Distance to the xz-plane = |y|
Step-by-step explanation:
The distance from P(x,y,z) to the xy-plane is by definition the magnitude of the vector that goes from the perpendicular projection of P over the xy-plane to the point P, which is exactly the magnitude of the vector (0,0,z) = |z| the absolute value of z
Similarly, the distance from P to the yz-plane is |x| and the distance from P to the xz-plane is |y|
Distance to the xy-plane = |z|
Distance to the yz-plane = |x|
Distance to the xz-plane = |y|
4*9+6 / -3
multiply 4 and 9
36 + 6 / -3
add 36 and 6
42 / -3
divide
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