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3 years ago

9

¿Cuale son los numero reales?

1 answer:

jarptica [38.1K]3 years ago

8 0

Answer:

The real numbers are any number that corresponds to a point on the line Real and can be classified into numbers natural, whole, rational and irrational. In other words, any real number is between minus infinity and plus infinity and we can represent it on the real line .

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What is the answer to 2 + (c + 0) = ?

ipn [44]

C=-2 because you would transfer to the other side making it negative. It can't be a negative so you divide -1 to 2. Making it -2.

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3 years ago

Evaluate f(-3) for f(x) = 2x.

Natasha_Volkova [10]

Answer: f(-3) = 2 x -3 = -6

3 0

4 years ago

Y varies directly with X and has a constant rate of change of 6. When the value of Y is 11, then the value of X could be _____.

Bogdan [553]

Answer: The correct option is (B) less than 2.

Step-by-step explanation: Given that Y varies directly with X and has a constant rate of change of 6.

We are to find the possible value of X when the value of Y is 11.

Since Y varies directly with X, so we can write

$Y\propto X\\\\\Rightarrow Y=kx~~~~~~~~~~~~~~~(i),~~~~~~~~~\textup{[where 'k' is the constant of variation]}$

Since the rate of change is constant and is equal to 6, so we must have

$k=6.$

So, from equation (i), we have

$Y=kX\\\\\Rightarrow Y=6X~~~~~~~~~~~~~~~~~~~~~~(ii)$

Now, when Y = 11, then from equation (ii), we get

$Y=6X\\\\\Rightarrow 11=6X\\\\\Rightarrow X=\dfrac{11}{6}$

Thus, the value of X is less than 2 when Y = 11.

Option (B) is CORRECT.

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3 years ago

Help pls ! 15−24÷4⋅2

Nady [450]

Answer:

9.28

Step-by-step explanation:

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3 years ago

Write the linear equation in slope intercept form 1,3 and -3,-5

oksian1 [2.3K]

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We have two points through which the line passes:

$(x_ {1}, y_ {1}) :( 1,3)\\(x_ {2}, y_ {2}): (- 3, -5)$

We found the slope:

$m = \frac{y_ {2} -y_ {1}} {x_ {2} -x_ {1}}$

Substituting we have:

$m = \frac {-5-3} {- 3-1} = \frac {-8} {- 4} = 2$

Thus, the equation is of the form:

$y = 2x + b$

We substitute one of the points and find the cut-off point:

$3 = 2 (1) + b\\3 = 2 + b\\3-2 = b\\b = 1$

Finally, the equation is:

$y = 2x + 1$

ANswer:

$y = 2x + 1$

3 0

4 years ago