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Dafna11 [192]
3 years ago
15

Precision

Physics
2 answers:
Schach [20]3 years ago
6 0

Answer:

how close a true value a measurement is

Viefleur [7K]3 years ago
6 0
The location of the object
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A sound wave with a waveenght of 2.5 meters traves 660 meters in 2 seconds calculate the frequemcy of the wave to cacuation the
finlep [7]

The frequency of the wave is 132 Hz

Explanation:

To calculate the speed of the wave, we can use the following formula:

v = \frac{d}{t}

where

d is the distance travelled by the wave

t is the time elapsed

For the sound wave in this problem, we have:

d = 660 m is the distance travelled

t = 2 s is the time interval considered

Substituting and solving for v, we find the speed of the sound wave:

v=\frac{660}{2}=330 m/s

Now we can calculate the frequency of the wave by using the wave equation:

v=f\lambda

where

v = 330 m/s is the speed of the wave

\lambda=2.5 m is the wavelength

f is the frequency

Solving for f, we find:

f=\frac{v}{\lambda}=\frac{330}{2.5}=132 Hz

Learn more about wavelength and frequency:

brainly.com/question/5354733

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#LearnwithBrainly

7 0
3 years ago
There is a decrease in power. It can be concluded that there has also been a change in: A)current or voltage.
liraira [26]

A current or voltage

5 0
3 years ago
Kingda Ka has a maximum speed of 57.2 m/s. Determine the height of the hill on this roller coaster. Explain to get full credit,
kodGreya [7K]

This question involves the concepts of the law of conservation of energy, kinetic energy, and potential energy.

The height of the hill is "166.76 m".

<h3>LAW OF CONSERVATION OF ENERGY:</h3>

According to the law of conservation of energy at the highest point of the roller coaster ride, that is, the hill, the whole (maximum) kinetic energy of the roller coaster is converted into its potential energy:

Maximum\ Kinetic\ Energy\ Lost = Maximum\ Potential\ Energy\ Gain\\\\&#10;\frac{1}{2}mv_{max}^2=mgh\\\\&#10;h=\frac{v_{max}^2}{2g}

where,

  • h = height of the hill = ?
  • v_{max} = maximum velocity = 57.2 m/s
  • g = acceleration due to gravity = 9.81 m/s²

Therefore,

h=\frac{(57.2\ m/s)^2}{2(9.81\ m/s^2)}\\\\&#10;

<u>h = 166.76 m</u>

Learn more about the law of conservation of energy here:

brainly.com/question/101125

7 0
3 years ago
A city bus travels along its route from Jackson Street 8 km to Aurora Avenue, where it turns and continues 13 km.
Elina [12.6K]

im a bit confused on what the question is:(

if its just asking for the total number of km traveled it would be 21 km

3 0
3 years ago
If a projectile is launched vertically from the Earth with a speed equal to the escape speed, how high above the earth's surface
Alecsey [184]

Answer: h = 3R

Explanation:

Using the law of conservation of energy,

Total energy at the beginning of the launch would be equal to total energy at any point.

kinetic energy + gravitational potential energy = constant

Initial energy of the projectile =\frac{1}{2}mv_e^2-\frac{GMm}{R}... (1)

where R is the radius of the Earth, M is the mass ofthe Earth, m is the mass of the projectile.

escape velocity, v_e=\sqrt{\frac{2GM}{R}}

Total energy at height h above the Earth where speed of the projectile is half the escape velocity:

\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h} ...(2)

(1)=(2)

⇒\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h} = \frac{1}{2}mv_e^2-\frac{GMm}{R}

⇒G\frac{Mm}{R}-G\frac{Mm}{R+h}= \frac{1}{2}m \frac{3}{4}v_e^2 =\frac{1}{2}m \frac{3}{4} (\sqrt{\frac{2GM}{R}})^2

⇒\frac{GM(R+h-R)}{R(R+h)} = \frac{3}{4}(\frac{GM}{R})

⇒\frac{h}{R+h} = \frac{3}{4}

⇒h = 3R

Thus, at height equal to thrice radius of Earth, the speed of the projectile would reduce to half of escape velocity.  

4 0
3 years ago
Read 2 more answers
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