Question

What is the slope of the line that contains the points (-1,2) and (3,3)?

Answer 1

Step-by-step explanation:

A(-1,2) and B(3,3) then AB=(4,1).

Normal vector

n=(-1,4)

Our line contains point A(-1,2) and has normal vector n=(-1,4) is

$(d) : - 1(x + 1) + 4(y - 2) = 0$

$(d ): - x - 1 + 4y - 8 = 0$

$(d) : - x + 4y - 9 = 0$

Answer 2

Answer:

1/4

Step-by-step explanation:

To find the slope of a line from two points we use

m = (y2-y1)/(x2-x1)

m = (3-2)/ (3--1)

   = (3-2)/(3+1)

  =1/4