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Nookie1986 [14]
3 years ago
8

What is the slope of the line that contains the points (-1,2) and (3,3)?

Mathematics
2 answers:
alukav5142 [94]3 years ago
5 0

Step-by-step explanation:

A(-1,2) and B(3,3) then AB=(4,1).

Normal vector

n=(-1,4)

Our line contains point A(-1,2) and has normal vector n=(-1,4) is

(d) :  - 1(x + 1) + 4(y - 2) = 0

(d ):  - x - 1 + 4y - 8 = 0

(d) :  - x + 4y - 9 = 0

Semmy [17]3 years ago
4 0

Answer:

1/4

Step-by-step explanation:

To find the slope of a line from two points we use

m = (y2-y1)/(x2-x1)

m = (3-2)/ (3--1)

   = (3-2)/(3+1)

  =1/4

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H + 12 = 31<br> equal what equation h=
Oksi-84 [34.3K]
Move 12 to the other side, making it negative
h=31-12
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3 years ago
In the accompanying figure, triangle ABC has coordinates A(0,3), B(7,3), C(7,7). What is the area of triangle ABC in square unit
ElenaW [278]

We know area of triangle = \frac{1}{2}  * base * height

In triangle ABC , AB is the base and BC is the height

Now we find the distance between A and B

Distance formula is \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}

A(0,3), B(7,3)

Distance AB = \sqrt{(7-0)^2 + (3-3)^2}

= \sqrt{(7)^2 } = 7

B(7,3), C(7,7)

Distance BC = \sqrt{(7-7)^2 + (7-3)^2}

= \sqrt{(4)^2 } = 4

area of triangle = \frac{1}{2}  * base * height

area of triangle = \frac{1}{2}  * AB * BC

= \frac{1}{2}  * 7 * 4 = 14 units ^2

4 0
3 years ago
daniel is using a scale factor of 10 to enlarge a class photo that measures 3.5 inches by 5 inches what are The dimensions Love
Sholpan [36]
35 inches by 50 inches
6 0
3 years ago
What is 1.08 to the power of <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D" id="TexFormula1" title="\frac{1}{5}" alt="
OlgaM077 [116]

Answer:

about \: 1.01551

Step-by-step explanation:

No it isn't, because:

{1.08}^{ \frac{1}{5} }  =  { \frac{108}{100} }^{ \frac{1}{5} }  =  { \frac{27}{25} }^{ \frac{1}{5} }  =  \sqrt[5]{ \frac{27}{25} }  = 1.01551

6 0
3 years ago
I NEED HELP PLZ ( WILL GIVE BRAINLYIST) ( NO LINKS)
AlladinOne [14]

9514 1404 393

Answer:

  66 cm²

Step-by-step explanation:

The area of the polygon is the sum of the areas of the triangle and the rectangle it sits on. The dimensions of the triangle can be found by examining the top/bottom dimensions shown and the left/right dimensions shown.

The width (base) of the triangle is the difference between the lengths of the bottom and top horizontal lines: (12 -9) cm = 3 cm.

The height of the triangle is the difference between the lengths of the left and right sides of the figure: (9 -5) cm = 4 cm.

The dimensions of the rectangle are shown a the bottom and the left sides of the figure.

  triangle area = 1/2bh = 1/2(3 cm)(4 cm) = 6 cm²

  rectangle area = LW = (12 cm)(5 cm) = 60 cm²

Total polygon area = 6 cm² + 60 cm² = 66 cm²

4 0
3 years ago
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