If DF = 170, find the value of x. Then find DE and EF. DE=3x + 20 EF=2x + 40

1 answer:

Julli [10]2 years ago

7 0

9514 1404 393

Answer:

DE = 86

EF = 84

Step-by-step explanation:

We assume that point E lies on segment DF, so that ...

DE + EF = DF

(3x +20) +(2x +40) = 170

5x = 110 . . . . . . . . . . . . . . . collect terms, subtract 60

x = 22 . . . . . . . . . . . . divide by 5

DE = 3×22 +20 = 66 +20 = 86

EF = 2×22 +40 = 44 +40 = 84

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Eddi Din [679]

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2 years ago

Marizza181 [45]

There are 12 possible arrangements.

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Considering that the blue cup has to be on one end, we consider the number of arrangements possible with the other 4 cups, then multiply by 2(considering the blue on each end).

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Considering green and yellow before red and purple, there are $2 \times 2 = 4$ outcomes(G-Y-R-P, G-Y-P-R, Y-G-R-P and Y-G-P-R).
Another two possible outcomes are yellow-purple and green-red, or vice-versa, thus 4 + 2 = 6 outcomes.
To account for the blue on the end, multiplying by 2. $2 \times 6 = 12$
There are 12 possible arrangements.