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OLEGan [10]
2 years ago
12

-0.75___-3/4 which one is greater

Mathematics
2 answers:
Zolol [24]2 years ago
6 0

Answer:

-3/4 is the greater than -0.75

arlik [135]2 years ago
3 0
I don’t think one is greather than the other they are equal
-0.75=-3/4
You might be interested in
Factor the following equations to find the zeros of the equation.
irina1246 [14]

The zeroes of the equation are (1,4)

Step-by-step explanation:

Given equation is:

y = x^2 - 5x + 4

We have to put y=0 in the equation to find zeroes of the equation

x^2-5x+4 = 0\\x^2 - 4x- x +4 = 0\\x(x-4)-1(x-4) = 0\\(x-4)(x-1) = 0\\x - 4 =0 => x = 4\\x-1 = 0 => x = 1

Hence,

The zeroes of the equation are (1,4)

Keywords: Equation, zeroes of an equation

Learn more about zeroes of equation at:

  • brainly.com/question/4168505
  • brainly.com/question/4228574

#LearnwithBrainly

4 0
3 years ago
What is the measure of angle A in the triangle below? Right triangle A B C is shown. Side B C has a length of 9 and hypotenuse A
klasskru [66]

Answer:

The answer is 30°

Step-by-step explanation:

I finished the test on edgen and passed

8 0
3 years ago
PLEASE HELPPPP ASAP!!!! I REALLY NEED IT! WILL MARK BRAINLIEST!!!!
11Alexandr11 [23.1K]

Answer:

3.3

Step-by-step explanation:

d = (10 - 4) + (8 - 3)

d = 6 + 5

d = square root of 11

d = 3.31662479 or 3.3

I'll be expecting that brainliest :)

6 0
3 years ago
Suppose you want to build a small walkway around your garden so that there is someplace to walk around and work on your vegetabl
wolverine [178]

Answer:

Approximately 3.5 feet - Option B

Step-by-step explanation:

Imagine that you have this walkway around the garden, with dimensions 30 by 20 feet. This walkway has a difference of x feet between it's length, and say the dimension 30 feet. In fact it has a difference of x along both dimensions - on either ends. Therefore, the increases length and width should be 30 + 2x, and 20 + 2x, which is with respect to an increases area of 1,000 square feet.

( 30 + 2x ) * ( 20 + 2x ) = 1000 - Expand "( 30 + 2x ) * ( 20 + 2x )"

600 + 100x + 4x^2 = 1000 - Subtract 1000 on either side, making on side = 0

4x^2 + 100x - 400 = 0 - Take the "quadratic equation formula"  

( Quadratic Equation is as follows ) - x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a},

x=\frac{-100+\sqrt{100^2-4\cdot \:4\left(-400\right)}}{2\cdot \:4}:\quad \frac{5\left(\sqrt{41}-5\right)}{2},

x=\frac{-100-\sqrt{100^2-4\cdot \:4\left(-400\right)}}{2\cdot \:4}:\quad -\frac{5\left(5+\sqrt{41}\right)}{2}

There can't be a negative width of the walkway, hence our solution should be ( in exact terms ) \frac{5\left(\sqrt{41}-5\right)}{2}. The approximated value however is 3.5081...or approximately 3.5 feet.

4 0
3 years ago
Which statement is false?
tankabanditka [31]

Answer:Choice A)  All points with an x-value of 3 are located in Quadrant I.

We can show it is false through the use of a counter example. For instance, the point (3, -5) is not in quadrant 1, but rather in quadrant 4.

We would need to say "all points with x value 3 and positive y value" to ensure the point is in quadrant 1.

7 0
3 years ago
Read 2 more answers
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