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ki77a [65]
3 years ago
14

I need help with my science about cells​

Mathematics
1 answer:
Alina [70]3 years ago
3 0

Answer:

a. pancreas

other body part is related to urinary system except pancreas as it is related to digestive

b. heart

it is a part of circulatory system whereas other are digestive

c. vagina

as it is female reproductive system

Step-by-step explanation:

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10.3<br> Problem Solving<br> 33/5 as a whole number
goblinko [34]

Answer:

6 and 3/5

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Integrate dx/3sinx+4cosx
german

\displaystyle\int\frac{\mathrm dx}{3\sin x+4\cos x}

A standard approach would be the tangent half-angle substitution:

t=\tan\dfrac x2\implies\mathrm dt=\dfrac12\sec^2\dfrac x2\,\mathrm dx

Then

\sin x=2\sin\dfrac x2\cos\dfrac x2\implies\sin x=\dfrac{2t}{1+t^2}

\cos x=\cos^2\dfrac x2-\sin^2\dfrac x2\implies\cos x=\dfrac{1-t^2}{1+t^2}

from which we get

\mathrm dx=\dfrac2{1+t^2}\,\mathrm dt

So the integral becomes

\displaystyle\int\frac{\frac2{1+t^2}}{\frac{6t}{1+t^2}+\frac{4(1-t^2)}{1+t^2}}\,\mathrm dt=\int\frac{\mathrm dt}{3t+2(1-t^2)}=-\int\frac{\mathrm dt}{2t^2-3t-2}

Rewrite the denominator as

2t^2-3t-2=(2t+1)(t-2)

and expand the integrand into its partial fractions:

\dfrac1{2t^2-3t-2}=\dfrac15\left(\dfrac1{t-2}-\dfrac2{2t+1}\right)

We have

\displaystyle-\frac15\int\frac1{t-2}-\frac2{2t+1}\,\mathrm dt=-\frac15(\ln|t-2|-\ln|2t+1|)+C

=\dfrac15\ln\left|\dfrac{2t+1}{t-2}\right|+C

=\dfrac15\ln\left|\dfrac{2\tan\frac x2+1}{\tan\frac x2-2}\right|+C

6 0
3 years ago
What is the answer? 4(-x+4)=12 ​
solniwko [45]
The answer is x=1 because you have to distribute and then divide
4 0
3 years ago
Please please please help
tankabanditka [31]

Answer:

-4/9

Step-by-step explanation:

-4 x 5 = -20

5 x 9 = 45

so you have -20/45

divide by 5 for both and you get -4/9

Hope this helps!!

5 0
3 years ago
In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6970 subjects randomly sele
Taya2010 [7]

Answer:

we will fail to reject the null hypothesis and conclude that the return rate is less than​ 20%.

Step-by-step explanation:

We are given;

Sample size;n = 6970

Success rate;X = 1334/6970 = 0.1914

Now, we want to test the claim that the return rate is less than p = 0.2, hence the null and alternative hypothesis are respectively;

H0: μ < 0.2

Ha: μ ≥ 0.2

The standard deviation formula is;

σ = √(x(1 - x)/n)

σ = √(0.1914(1 - 0.1914)/6970)

σ = 0.004712

Now for the test statistic, formula is;

z = (x - μ)/σ

z = (0.1914 - 0.2)/0.004712

z = -1.825

From the a-distribution table attached, we have a value of 0.03362.

This p-value gotten from the z-table is more than the significance value of 0.01. Thus, we will fail to reject the null hypothesis and conclude that the return rate is less than​ 20%.

4 0
4 years ago
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