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3 years ago

This question please i need help

Mathematics

1 answer:

grin007 [14]3 years ago

6 0

Answer: the picture has no answer it's invalid but I will try:

X is a 90 degree angle other than that I can't do anything

Step-by-step explanation:

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Plz help me with this

8090 [49]

Answer:

8.216 put a line on top of the six because it's repeating

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Someone help me with this

Alenkasestr [34]

Answer:

70°

Step-by-step explanation:

ABC is the center angle that sees the arc and is twice as angle ADC so the measure of ABC is e × 35 = 70

3 0

3 years ago

Read 2 more answers

The train clock run fast and gain 4 minutes every 3 days. How many minutes and seconds will it have gained at the end of 2 days.

Katarina [22]

Answer:

2 minutes, 40 seconds

Step-by-step explanation:

set up a proportion and cross-multiply:

4/3 = x/2

3x = 8

x = 2 2/3 which is 2 minutes, 40 seconds

8 0

3 years ago

the length of a rectangle is 3 units shorter than one -third of the width, x. Which expression represents the perimeter of the r

Mariana [72]

Answer:

A) $\frac{8}{3} x - 6$

Step-by-step explanation:

Let the width of the rectangle be x units.

$\therefore \: length \: of \: rectangle = \frac{1}{3} x - 3 \\ Perimeter \: of \: rectangle = 2(l + w) \\ = 2 \bigg( \frac{1}{3} x - 3 + x \bigg)\\ = 2 \bigg( x + \frac{1}{3} x - 3 \bigg)\\ = 2 \bigg( \frac{3x + x}{3} - 3 \bigg)\\ = 2 \bigg( \frac{4x}{3} - 3 \bigg) \\ = 2 \bigg( \frac{4x}{3} - 3 \bigg) \\ = \frac{2 \times 4x}{3} -2 \times 3 \\ \purple{ \bold{{Perimeter \: of \: rectangle = \frac{8}{3} x - 6}}}$

8 0

3 years ago

Please help with geometry. 20 points, and another question worth 98 on my profile!

vovikov84 [41]

Answer:

Part 1) m∠1 =(1/2)[arc SP+arc QR]

Part 2) $PR^{2} =PS*PT$

Part 3) PQ=PR

Part 4) m∠QPT=(1/2)[arc QT-arc QS]

Step-by-step explanation:

Part 1)

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

we have

m∠1 -----> is the inner angle

The arcs that comprise it and its opposite are arc SP and arc QR

m∠1 =(1/2)[arc SP+arc QR]

Part 2)

we know that

The <u>Intersecting Secant-Tangent Theorem,</u> states that the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

In this problem we have that

$PR^{2} =PS*PT$

Part 3)

we know that

The <u>Tangent-Tangent Theorem</u> states that if from one external point, two tangents are drawn to a circle then they have equal tangent segments

In this problem

PQ=PR

Part 4)

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

In this problem

m∠QPT -----> is the outer angle

The arcs that it encompasses are arc QT and arc QS

therefore

m∠QPT=(1/2)[arc QT-arc QS]

4 0

3 years ago