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bogdanovich [222]
3 years ago
15

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Lines AB and CD

are parallel. The coordinates of point A are (-2,5), the coordinates of point B are (6,3), and the coordinates of point D are (8,5). The equation of line CD is y =
Mathematics
1 answer:
NARA [144]3 years ago
5 0

Lines AB and CD are parallel. Using the given coordinates

The equation of line CD is y=-\frac{1}{4}x+7

Given :

Lines AB and CD are parallel. The coordinates of point A are (-2,5), the coordinates of point B are (6,3),the coordinates of point D are (8,5)

When two lines are parallel then their slopes are equal

Lets find the slope of AB using the given points

A is (-2,5)  and B is (6,3)

Find slope using slope formula

slope m =\frac{y_2-y_1}{x_2-x_1} =\frac{3-5}{6+2} =-\frac{1}{4}

Slope of AB is -\frac{1}{4}

Slope of AB  and CD  are same

Slope of CD is -\frac{1}{4}

Now we find equation of line CD y=mx+b

Use point slope formula

y-y_1=m(x-x_1)\\

use the given point D(8,5) and slope m

Substitute the values

y-5=-\frac{1}{4} (x-8)\\\\y-5=-\frac{1}{4}x+2\\y=-\frac{1}{4}x+2+5\\y=-\frac{1}{4}x+7

The equation of line CD is y=-\frac{1}{4}x+7

Learn more : brainly.com/question/17301100

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Long division<br> 3x+1/6x^6+5x^5+2x^4-9x^3+7x^2-10x+2
inna [77]
(6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2) / (3x+1)

We divide first number from first parenthesis with first number from second parenthesis. Then the resulting number we multiply by all numbers in second parenthesis and substract from first parenthesis.

6 x^{6}/3x = 2 x^{5} \\  \\ 6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2 - 6 x^{6} -2 x^{5} = 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2\\

We repeat previous steps until we run out of numbers:
3x^{5}/3x=x^{4} \\ \\ 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2-3x^{5}-x^{4}= \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2 \\ \\ \\ x^{4}/3x= \frac{1}{3} x^{3} \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2-x^{4}- \frac{1}{3} x^{3}= \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2 \\ \\ \\ - \frac{28}{3} x^{3}/3x= - \frac{28}{9} x^{2} \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2+ \frac{28}{3} x^{3}+ \frac{28}{9} x^{2} = \\ \\ \frac{91}{9} x^{2}-10x+2
\frac{91}{9} x^{2}/3x=\frac{91}{27} x \\ \\ \frac{91}{9} x^{2}-10x+2-\frac{91}{9} x^{2}-\frac{91}{27} x= \\ \\ -\frac{361}{27} x+2 \\ \\ \\ -\frac{361}{27} x/3x=-\frac{361}{81} \\ \\ -\frac{361}{27} x+2+\frac{361}{27}x+\frac{361}{27}= \\ \\ \frac{415}{27}

We are left with a number that has no x inside. This is remainder.
The final solution is sum of all these solutions and remainder:
(2 x^{5}+x^{4}+\frac{1}{3} x^{3} - \frac{28}{9} x^{2} +\frac{91}{27} x)+(-\frac{361}{81} )
6 0
3 years ago
Calculate the approximate probability that at least 2 children have been diagnosed with ASD among the 200 selected children.
mixas84 [53]

Answer:

The approximate probability that at least 2 children have been diagnosed with ASD among the 200 selected children is

0.01 or 1%.

Step-by-step explanation:

Number of selected children = 200

The probability of no child been diagnosed with ASD = P(None) = 198/200 = 0.99

Therefore, the probability of at least two children been diagnosed with ASD = 1 - 0.99 = 0.01.

This is the same as:

If 2 children have been diagnosed with ASD,

therefore, the approximate probability that at least 2 children have been diagnosed is:

2/200 = 0.01.  This value is equal to 1%.

The above are summed up in:

The probability of at least one = 1/200 = 0.05

Therefore, the probability of at least two = 0.05 * 2 = 0.01

b) Generally, to find the probability of at least one event happening, we calculate the probability of none and then subtract that result from 1. That is, P(at least one) = 1 – P(none).  For two events happening, the sum of the probability of at least one in two places is deducted from 1 to get the probability of at least two.

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3 years ago
1)<br> 0.1.x - 0.006 = 0.08.x + 0.134
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Answer:

x=7

Step-by-step explanation

left part + 0.006 = right part + 0.006

---->  0.1x   = 0.08x+0.14

left part -0.08x =right part - 0.08x

----> 0.02x=0.14

             x=7

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One inch of board is left
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