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Korvikt [17]
3 years ago
11

Neeeedddd Helpppp Plzzzzz

Mathematics
1 answer:
elena-s [515]3 years ago
3 0

Answer:

2x+46+3x-6 = 90

5x+40 = 90

5x = 90-40

5x = 50

x = 50/5

x = 10

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

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3 0
3 years ago
Find the volume of the solid generated when the region bounded by y=4x and y=16x is revolved about the​ x-axis. A coordinate sys
givi [52]

Answer:

The value is V(x) =  1706.7 \pi

Step-by-step explanation:

From the question we are told that

The first equation is y=16\sqrt{x}

The second equation is y=4x

Generally the first point of intersection of the first and second equation is x = 0

Generally the obtain the second point of intersection of the two equation we equate the two equations

So

=> 16\sqrt{x} = 4x

=> \sqrt{x} = \frac{4x}{16}

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Generally the from washer method we have

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So

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and

G(x) =  4x

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V(x) =  \int\limits^4_0 {\pi [(16\sqrt{x})^2 - (4x)^2]} \, dx

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=>V(x) =  \pi [256 \frac{x^2}{2} - 16 \frac{x^3}{3} ]|\left 4} \atop 0}} \right.

=> V(x) =  \pi [256 * \frac{ 4^2}{2}  - 16 * \frac{4^3}{3} ]

=> V(x) =  1706.7 \pi

6 0
3 years ago
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