All categories

3 years ago

Neeeedddd Helpppp Plzzzzz

Mathematics

1 answer:

elena-s [515]3 years ago

3 0

Answer:

2x+46+3x-6 = 90

5x+40 = 90

5x = 90-40

5x = 50

x = 50/5

x = 10

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

You might be interested in

What is the missing term?

klio [65]

Answer:

-6

Step-by-step explanation:

3 x -2 = -6

You know this because you can see the pattern, whatever the column box is its always multiplied by the number its going on both vertical and horizontal.

6 0

3 years ago

Jake is buying a piece a recycle art from Lana he is starting by giving her $50 and farmers to pay her five dollars a week until

wel

Answer:

who's the CrAZy??

Step-by-step explanation:

8 0

4 years ago

Jonathan cannot afford to pay cash for the cellphone in the Callnow shop. He can only afford to pay R400 per month. Determine th

inessss [21]

Answer:

9 months

Step-by-step explanation:

Becase in 8 months he can pay 3200 but another month also need to pay ramining money

5 0

3 years ago

Help please ASAP I really need someone to help me please I posted the question 3 times please y’all

Tcecarenko [31]

Answer:

The answer is x = 24 , y = 8√3

Hope it will help :)

3 0

3 years ago

Find the volume of the solid generated when the region bounded by y=4x and y=16x is revolved about the x-axis. A coordinate sys

givi [52]

Answer:

The value is $V(x) = 1706.7 \pi$

Step-by-step explanation:

From the question we are told that

The first equation is $y=16\sqrt{x}$

The second equation is $y=4x$

Generally the first point of intersection of the first and second equation is x = 0

Generally the obtain the second point of intersection of the two equation we equate the two equations

=> $16\sqrt{x} = 4x$

=> $\sqrt{x} = \frac{4x}{16}$

=> $x = 4$

Generally the from washer method we have

$V(x) = \int\limits^4_0 {\pi [(H(x))^2 - (G(x))^2]} \, dx$

$H(x) = 16\sqrt{x}$

and

$G(x) = 4x$

$V(x) = \int\limits^4_0 {\pi [(16\sqrt{x})^2 - (4x)^2]} \, dx$

=> $V(x) = \int\limits^4_0 {\pi [256x - 16x^2]} \, dx$

=> $V(x) = \pi [256 \frac{x^2}{2} - 16 \frac{x^3}{3} ]|\left 4} \atop 0}} \right.$

=> $V(x) = \pi [256 * \frac{ 4^2}{2} - 16 * \frac{4^3}{3} ]$

=> $V(x) = 1706.7 \pi$

6 0

3 years ago