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Korvikt [17]
2 years ago
11

Neeeedddd Helpppp Plzzzzz

Mathematics
1 answer:
elena-s [515]2 years ago
3 0

Answer:

2x+46+3x-6 = 90

5x+40 = 90

5x = 90-40

5x = 50

x = 50/5

x = 10

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

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How to graph 200-25x=y
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Simplifying
y = -25x + 200

Reorder the terms:
y = 200 + -25x

Solving
y = 200 + -25x

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Simplifying
y = 200 + -25x
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3 years ago
PLS HELP IT IS EZZZZZZZZZZZZZZ Latavia purchased adult and child tickets for the fall festival. Tickets cost $14.88 for each adu
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Answer:

14.88x + 8.88y

Step-by-step explanation:

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2 years ago
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A hockey player strikes a hockey puck. The height of the puck increases until it reaches a maximum height of 3 feet, 55 feet awa
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Answer:

Second puck travels farther

Step-by-step explanation:

Maximum height of first puck = 3 feet

The height of a second hockey puck is modeled by:

y=x\left(0.15-0.001x\right)

y=0.15x-0.001x^2

To find maximum height of second puck

y'=0.15-0.002x

Equate the derivative equals to 0

0.15-0.002x=0

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75 = x

At x = 75

y=0.15(75)-0.001(75)^2=5.625

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5 0
2 years ago
Cual es la derivada de ()=√x sin
fgiga [73]

Answer:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

Step-by-step explanation:

We assume that the function of interest is:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

3 0
3 years ago
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