I have all the answers here so take this
T = 3.5 secs
Velocity (v) = g * t = 10 m/s^2 * 3.5 sec = 35 m/s
Answer:
The magnitude of the frictional force is 48.02 N
Explanation:
Mass of box = 20 kg
Weight of the box (Normal reaction) = mass × acceleration due to gravity = 20 ×9.8 = 196 N
Horizontal force applied = 48 N
Coefficient of friction = horizontal force ÷ normal reaction = 48 ÷ 196 = 0.245
Frictional force = coefficient of friction × normal reaction = 0.245 × 196 N = 48.02 N
Answer:
work done by tension force on the twirled stone must be ZERO always
Explanation:
As we know that work done by a force on an object is given as


here we know that
= angle between force and displacement
now we know that tension in the string and displacement of the object is always perpendicular to each other when the rock is twirled in circular path.
so we can say for this motion of the stone

so work done by tension force on the twirled stone must be ZERO always
Answer:

Explanation:
It is given that,
Speed of P- waves, v = 9 km/s = 9000 m/s
The density of rock is about 
We need to find the average bulk modulus of Earth's crust. Let it is given by B. So,

So, the bulk modulus of the Earth's crust is
.