Answer:
Xc= 17.267 Ω, Z= 415.5 Ω, I= 0.537 A
Explanation:
Em = 223 V
f= 300 Hz, R = 222 Ω, L = 147 mH, C = 23.1 μF
a)
Capacitive reactance = Xc=?
Xc= ![\frac{1}{2\pi fC}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%5Cpi%20fC%7D)
Xc=1/2pi *399*23.1*10^-6
Xc= 17.267 Ω
b).
Z=![\sqrt{ R^2 + (Xl - Xc)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%20R%5E2%20%2B%20%28Xl%20-%20Xc%29%5E2%7D)
Xl= 2π * f * L
Xl= 2π * 399 * 147 * ![10^{-3}](https://tex.z-dn.net/?f=10%5E%7B-3%7D)
Xl= 368.5 Ω
Z=
= ![\sqrt{222^2 + (368.5 - 17.267)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B222%5E2%20%2B%20%28368.5%20-%2017.267%29%5E2%7D)
Z= 415.5 Ω
c).
Current:
I= V / Z= Em / Z
I= 223/415.5
I= 0.537 A
Answer:
I think the answer is
a "cookbook" recipe for performing scientific investigations
Explanation:
Answer : 413.44N
Here it is given that an elevator is moving down with an acceleration of 3.36 m/s² . And we are interested in finding out the apparent weight of a 64.2 kg man . For the diagram refer to the attachment .
- From the elevator's frame ( non inertial frame of reference) , we would have to think of a pseudo force.
- The direction of this force is opposite to the direction of acceleration the frame and its magnitude is equal to the product of mass of the concerned body with the acceleration of the frame .
- When a elevator accelerates down , the weight recorded is less than the actual weight .
From the Free body diagram ,
- Mass of the man = 64.2 kg
Answer:
The value is
Explanation:
From the question we are told that
The mass of the car is
The acceleration is ![a= 8.9 \ m/s^2](https://tex.z-dn.net/?f=a%3D%20%208.9%20%5C%20%20m%2Fs%5E2)
Generally the net force applied on the rope is mathematically represented as
![F_{net} = T - W](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%20%20%3D%20%20T%20-%20%20W)
Here W is the weight of the car which is evaluated as
=> ![W = 6526 * 9.8](https://tex.z-dn.net/?f=W%20%3D%20%206526%20%20%2A%209.8)
=> ![W = 63954.8 \ N](https://tex.z-dn.net/?f=W%20%3D%20%2063954.8%20%5C%20%20N)
Generally the net force can also be mathematically represented as
So
![m * a = T - 63954.8](https://tex.z-dn.net/?f=m%20%2A%20a%20%20%3D%20%20T%20%20-%20%2063954.8)
=> ![6526 * 8.9 = T - 63954.8](https://tex.z-dn.net/?f=6526%20%20%2A%20%208.9%20%3D%20%20T%20%20-%20%2063954.8)
=>