Solve 2x +8≤10 or 2x+8>20 please i need answers ASAP

Mathematics

1 answer:

devlian [24]3 years ago

8 0

Answer:

the think the answer is A. x ≤ 1 or x 6 >

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Write an e explicit formula for an, the nth term of the sequence 22, 19, 16, ...

alexira [117]

Answer:

$a_{n} = 22 + (-3)(n - 1)$

Step-by-step explanation:

The first term is 22. It looks like each term after that is the term before, plus a negative 3.

a-sub-one = 22

common difference = d= -3

Formula for $a_{n}$ :

$a_{n} = 22 + (-3)(n - 1)$ = 25 - 3n

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3 years ago

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garri49 [273]

Do you mean restaraunt?

Every 10th customer
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3 years ago

find the zeros of 2x^2 - 16x + 27 using the quadratic formula. be sure to simplify the expression. Can someone please show me ho

____ [38]

For a quadratic of the form $f(x)=ax^2+bx+c$ , we have the quadratic formula
$x=\dfrac{-b \pm \sqrt{b^2 -4ac} }{2a}$ ,
where a is the coefficient (number before the variable) of the squared term, b is the coefficient of the linear term, and c is the constant term.

So, given $2x^2-16x+27=0$ , we can get that $a=2, \ b=-16$ , and $c=27$ . We substitute these numbers into the quadratic formula above.

$x=\dfrac{-(-16) \pm \sqrt{(-16)^2 -4(2)(27)} }{2(2)}$

$x=\dfrac{16 \pm \sqrt{(256 -216)} }{4}$

$x=\dfrac{16 \pm \sqrt{40} }{4}$

$x=\dfrac{16 \pm 2\sqrt{10} }{4}$

$x=4+ \frac{\sqrt{10}}{2}, \ x=4- \frac{\sqrt{10}}{2}$

This is our final answer.

If you've never seen the quadratic formula, you can derive it by completing the square for the general form of a quadratic. Note that the $\pm$ symbol (read: plus or minus) represents the two possible distinct solutions, except for zero under the radical, which gives only one solution.