19x³ + (14x + 4x³)=
You can assume that there is a 1 in front of the parentheses, so you can distribute the one to each term in the parentheses.
19x³ + 1(14x+4x³)=
19x³ + 14x + 4x³=
Then combine like terms to get 23x³ + 14x.
So 19x³ + 14x + 4x³= 23x³ + 14x
You multipy 7/8 and 6 and then simplify if needed to get how long it will take
$167.... That an expensive tickets
Answer:
Adult Tickets: 173
Student Tickets: 43
Explanation:
- To solve this problem, you'll need to set up a system of equations.
- Assume a = # of adult tickets sold
- Assume s = # of student tickets sold
2: a + s = 216; 1: 10.25a+ 8s= 2117.25
2: <<As the total number of tickets sold from both sides is equal to 216>>
1: <<Each adults ticket (a) costs $10.25 and each student ticket (s) costs $8, and the total amount of money earned (2117.25) from sales is the combination of these two))>>
- Note that there are two ways to solve systems of equations (by elimnation and substitution), in this case I'll use elimnation as substitution requires one of the variables in one of the two equations to be isolated.
- In this case, I'll elimnate a.
a + s = 216
10.25a + 8s = 2117.25
- In order to elimnate a, it has to be equal to - 10.25 so that it cancels out + 10.25 (so you have to multiply everything on the first equation by 10.25 ((what you do to one part, you'll do to all the other parts)).
-10.25a -10.25s = -2214
10.25a + 8s = 2117.25
- a cancels, and now you solve accordingly.
-2.25s/-2.25 = -96.75/-2.25
s = 43
- You could solve for a using this same method, but it's easier to use the first formula <<a+s=216>> to find a.
a + 43 = 216
- 43 -43
a = 173
